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When positive integer n is divided by 3, the remainder is 2 [#permalink]
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16 Mar 2009, 23:28
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This topic is locked. If you want to discuss this question please repost it in the respective forum. When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15? (1) n2 is divisible by 5 (2) t is divisible by 3 OPEN DISCUSSION OF THIS QUESTION IS HERE: whenpositiveintegernisdividedby3theremainderis86155.html
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Last edited by Bunuel on 02 Jun 2013, 04:56, edited 3 times in total.
Edited the question and added the OA



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Re: DS  What is the Remainder ? [#permalink]
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01 Oct 2009, 01:06
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This solution is only detailed for better understanding. Hope it helps....
n = 3a + 2 t = 5b + 3 What is the remainder when nt/15?
1) n2 is divisible by 5 2) t is divisible by 3
1) n  2 is divisible by 5.
n = 3a + 2 n  2 = 3a 3a is divisible by 5 and therefore by 15
nt = 3a(5b + 3) + 2(5b + 3) =15ab + 9a + 10b + 6 15ab and 9a are divisible by 15, 10b: no info from (1) INSUFFICIENT
2) t = 5b + 3, so 5b is divisible by 3 and therefore, by 15.
nt = 15ab + 9a + 10b + 6 10b is divisible by 15 15ab and 9a: no info from (2) INSUFFICIENT
When you combine (1) and (2)... 15ab, 9a, and 10b are divisible by 15. Therefore, nt = 15ab + 9a + 10b + 6 =15(x) + 6
C.



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Re: DS  What is the Remainder ? [#permalink]
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When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?From the stem: \(n=3p+2\) and \(t=5q+3\). \(nt=15pq+9p+10q+6\), we should find the remainder when this expression is divided by 15. (1) n2 is divisible by 5 > \(n2=5m\) > \(n=5m+2=3p+2\) > \(5m=3p\), \(15m=9p\) > \(nt=15pq+ 9p+10q+6=15pq+ 15m+10q+6\). Clearly \(15pq\) and \(15m\) are divisible by 15, so remainder by dividing these components will be 0. But we still know nothing about \(10q+6\). Not sufficient. (2) t is divisible by 3 > means that \(5q+3\) is divisible by 3 > 5q is divisible by 3 or q is divisible by 3 > \(5q=5*3z=15z\) > \(10q=30z\) > \(nt=15pq+9p+ 10q+6=15pq+9p+ 30z+6\). \(15pq\) and \(30z\) are divisible by 15. Know nothing about \(9p+6\). Not sufficient. (1)+(2) \(9p=15m\) and \(10q=30z\) > \(nt=15pq+ 9p+ 10q+6=15pq+15m+30z+6\). Remainder when this expression is divided by 15 is 6. Sufficient. Answer: C. OR:From the stem: \(n=3p+2\) and \(t=5q+3\). (1) n2 is divisible by 5 > \(n2=5m\) > \(n=5m+2\) and \(n=3p+2\) > general formula for \(n\) would be \(n=15k+2\) (about deriving general formula for such problems at: goodproblem90442.html#p723049 and manhattanremainderproblem93752.html#p721341) > \(nt=(15k+2)(5q+3)=15*5kq+15*3k+10q+6\) > first two terms are divisible by 15 (\(15*5kq+15*3k\)) but we don't know about the last two terms (\(10q+6\)). Not sufficient. (2) t is divisible by 3 > \(t=3r\) and \(t=5q+3\) > general formula for \(t\) would be \(t=15x+3\) > \(nt=(3p+2)(15x+3)=15*3px+9p+15*2x+6\). Not sufficient. (1)+(2) \(nt=(15k+2)(15x+3)=15*15kx+15*3k+15*2x+6\) this expression divided by 15 yields remainder of 6. Sufficient. Answer: C.
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Re: DS  What is the Remainder ? [#permalink]
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01 Dec 2009, 19:44
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I think plugging numbers is the easiest way to do this. This question is about pattern recognition. By listing out the possible solutions for each, you can see a definite pattern. Possible Solutions for n given stem 2, 5,8,11,14,17,20,23,26,29,32,35,38,41... Possible solutions for t given stem 3,8,13,18,23,28,33,38,43,48,53,58... I. Using n2 is divisble by 5, you get n=17,32,47..., notice the difference is 15, meaning each remainder will be the same when multiplying (Note that it is important that they specify integers) However this gives us no indication as to the remainder of t  Insuff II Using t is divisible by 3, you get t=3,18,33,48... again, the difference is 15, meaning each remainder will be the same. No indication of n insuff You know that each remainder will be the same (in this case 6), C is suff since each individual number when divided by 15 will give the same remainder. Thoughts?
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Re: DS  What is the Remainder ? [#permalink]
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30 Apr 2009, 01:01
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I looked at option 2 first. The question can be rewritten as (NT/5*3). according to option 2, t is divisible by 3. But we can not tell if N will be divisible by 5 or not......insuff.
Lets analyse option 1. NT can be written as (N2+2)T which is (N2)T + 2T. So NT/15 = ((N2)T + 2T)/15 or (N2)T/5*3 + 2T/5*3 There is no way you can determine the divisibilty of T.......insuff.
If u combine 1 & 2 u know that T is divisible by 3 but there will be a 2/5 factor remaining which indicates that NT is not completely divisible by 15. Thats what we are looking for.......... Correct me if i went wrong...



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Re: DS  What is the Remainder ? [#permalink]
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04 Sep 2011, 23:35
Here's more of a plain English explanation, for those who like that sort of thing. An important principle here is that you can multiply remainders. For instance, 10/7 = 1 r2 and 9/7 = 1 r3. 10*9/7 = 12 r6. See? Remainder 2 * remainder 3 = remainder 6. Notice that if the resulting remainder is greater than the divisor, it wraps around again. 10/4=2 r 2 and 15/4=3 r 3. 10*15/4 should be remainder 6, but since 4 goes into 6, there is only 2 left. The actual result is 17 r2. So, back to our problem. Using the prompt and statement 1, we know that both n/3 and n/5 have remainders of 2. We also know that t/5 has a remainder of 3. So, if we just wanted to know the remainder when nt is divided by 5, we could multiply our remainders: 2 for n and 3 for t = 6. Since 5 goes into 6, we would be left with a remainder of 1. However, since we’re dealing with 15, it’s more complicated. We know the remainder when n is divided by 15. Since n must be 2 more than a multiple of 3 and 2 more than a multiple of 5, it will also be 2 more than a multiple of 15: 17, 32, 47 . . . We don’t know about t, though, unless we bring in statement 2. Once we do, we know that it is not only 3 more than a multiple of 5, but also an exact multiple of 3. Out of our original list (3, 8, 13, 18, 23, 28, 33 . . .basically, every number that ends in 8 or 3), this leaves 3, 18, 33, 48 . . . i.e., 3 more than a multiple of 15. Now we can multiply our remainders. n/15 has a remainder of 2 and t/15 has a remainder of 3, so nt/15 has a remainder of 6.
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Re: DS  What is the Remainder ? [#permalink]
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16 Mar 2009, 23:29
I tried to proceed in this way: n = 3a+2 t = 5b+3 So nt = 15ab+9a+10b+6 .... no useStmt1: if n2 = 5x so, n = 5x+2. Now plugged in n = 17. Remainder will be 2 while divided by 15..... Hence, n = 15M + 2 Stmt2: if t = 3y plugged in 18 and the remainder is 3 while divided by 15 Hence, t = 15N +3 stmt 1+ stmt 2: nt = (15M+2)*(15N+3)..... remainder is 6 ....suffice ...but this way it's too much confusing and time consuming....do you suggest any other way?
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Re: DS  What is the Remainder ? [#permalink]
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30 Mar 2009, 00:46
n = 17 ( the last digit of n had to be either 2 or 7 since n2 mod 5 =0, any number divisible by 5 has to have last digit as 0 or 5 therefore n2=last digit 0 or 5, n= last digit 2 or 7 ) t= 18 ( t is divisible by 3, the 1st no. that is divisible by 3 and yields 3 as remainder is 18 )
n*t mod 15, remainder = 6 (not 2, do not reduce )



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Re: DS  What is the Remainder ? [#permalink]
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17 Apr 2009, 08:54
sondenso wrote: priyankur_saha@ml.com wrote: I tried to proceed in this way: n = 3a+2 t = 5b+3 So nt = 15ab+9a+10b+6 .... no use
I stop here and deduct: whether nt divisible by 15 depends on "9a+10b+6" 1. n2 (=3a) divisible by 5 so a must be divisible by 5, or a =5k , not suff 2. t3 (=5b) divisible by 3 so b must be divisible by 3, or b=3r, not suff
1 and 2 combined: 9a+10b+6 =45k +30r+6 divided by 15, the remainder must be 6, suff Picking number may be confusing and intimidating. so solving equation would be best.
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Re: DS  What is the Remainder ? [#permalink]
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28 Apr 2009, 07:11
scthakur wrote: priyankur_saha@ml.com wrote: How to proceed? Plug in numbers or algebra?
When positive integer n is divided by 3, the remainder is 2; and when positive integer t is divided by 5, the remainder is 3. What is the remainder when the product nt is divided by 15?
1) n2 is divisible by 5
2) t is divisible by 3 What is the OA. Somehow, I got E. From the question, n = 3a + 2, t = 5b + 3. Hence, nt = 15ab + 9a + 10b + 6 From stmt1: n = 5x + 2 = 3a + 2 or, 3a = 5x. Hence, nt = 15ab + 15x + 10b + 6....insufficient. Also, including stmt2: t=3y = 5b+3 Hence, nt = 15ab + 15x + 6y And, when nt is divided by 15, remainder will have different values....hence, E. Please see above for the solutions  the OA is C, and the remainder is 6. Great little problem!



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Re: DS  What is the Remainder ? [#permalink]
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01 Oct 2009, 09:06
Here is one other way of solving the problem.
It is given in the question stem 
n when divided by 3 leaves a remainder 2 ==> n2 is divisible by 3. t when divided by 5 leaves a remainder 3 ==> t3 is divisible by 5.
Question being asked is what is the remainder when nt is divided by 15.
Clue 1 ==> it is given n2 is divisible by 5 and from given information, we know n2 is also divisible by 2 ==> n2 is divisible by 15. But nothing is mentioned abt t. Hence insufficient clue.
Clue 2 ==> it is given t is divisible by 3, we can derive that t3 is also divisible by 3. From the given information, we know t3 is divisble by 5 ==> t3 is divisible by 3 and 5 ==> t3 is divisible by 15. Nothing is mentioned abt n. Hence insufficient clue.
Combine both the clues
n2 = 15a ==> n = 15a + 2 t3 = 15b ==> t = 15b + 3
nt = (15a + 2)(15b + 3) ==> 15.15.a.b + 15.3.a + 15.2.b + 6
Clearly first 3 terms are divisible by 15. So the remainder should be 6.
Hence both the clues are sufficient to say the remainder of nt.



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Re: DS  What is the Remainder ? [#permalink]
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02 Oct 2009, 13:12
what's up guys? i too originally missed this question during a practice exam. However, after reviewing it without time constraints, I realized that even when you don't understand a DS problem, always employ logic if you have to guess. from the stem, given: n= 3x+2 t= 5y+3 the best approach i discovered is simply to algebraically determine what n and t are in order to determine what the remainder of nt is (i) given (n2)/5 which can be expressed as n2 = 5x now solve for n using the equation for n as given in the stem and substitute for x using (i) n2= 5x, x= (n2)/5, now plugging into n as given in stem: n = 3((n2)/5)+2 this solves for n = 2. However, since not given anything for t, can eliminate A&D (ii) now, in this statement, t is divisible by 3 can be written as t = 3y now plugging in this equation into the equation given in the stem ( t = 5y+3) and substituting y = t/3 as given in (ii): t = 5(t/3) +3.......solving for this equation yields t=9/2. However, this statement gives nothing about n as required to solve for the remainder of nt/15. Hence, we can eliminate B. now combined: n=2 and t= 9/2.........nt = 9 no need to solve for remainder! However, if you chose to calculate, you would soon realize that the remainder is 0. Try it and see for yourself..... According to sojafon: nt = 15ab + 9a + 10b + 6. However, ab+9a+10b is not equal to X from a distributive property standpoint as assumed by 15X+6. Therefore the remainder is not 6 as assumed. This is the only true and proven method I can see to be employed in order to solve this problem. However, if you were to employ a systematic approach, you will see that (i) gives nothing about t, which means eliminate AD. And (ii) says nothing about n, eliminate B. This leaves you with a 50/50 guess for C or E. OA is C.



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Re: DS  What is the Remainder ? [#permalink]
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04 Oct 2009, 21:54
embrya2k wrote: According to sojafon: nt = 15ab + 9a + 10b + 6. However, ab+9a+10b is not equal to X from a distributive property standpoint as assumed by 15X+6. Therefore the remainder is not 6 as assumed. OA is C. Incorrect. 15 wasn't factored out of 15ab alone, but 9a and 10b as well. I showed that 15ab, 9a and 10b are all divisible by 15 when you combine (1) and (2) and rewrote 15ab + 9a + 10b + 6 as 15x+6 to make the answer more obvious. nt = 15ab + 9a + 10b + 6, nt = 15x + 6 x is just a variable that represents the sum/value that's left after factoring 15 out of 15ab + 9a + 10b. This is essentially the same as nt = 15p + 15q + 15r + 6 nt =15(p + q + r) + 6, Let x be the sum of p, q and r. x = p + q + r nt = 15x + 6.



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Re: DS  What is the Remainder ? [#permalink]
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12 Nov 2009, 19:50
I used the same method as priyankur_saha. I think the answer is C. Also if using numbers , N=17 and T =18 remainder is 6. The only problems with plugging in numbers is that you are not sure if the number you picked represent all cases. So although the first method is longer, I would prefer it over the number plugging way. However, on the test, if you don't have the time to invest, use 17 and 18.
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Re: DS  What is the Remainder ? [#permalink]
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14 Nov 2009, 00:26
Yeah. Solving these type of question by algebra is better option than plugging the number as sometimes we forget to put the the different kind of numbers.
IMO C, and remainder is 6.



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Re: DS  What is the Remainder ? [#permalink]
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14 Nov 2009, 00:46
I agree that the answer is C. I solved it using the algebraic approach, but again... this is not a very fast approach.
From the problem statement we know: n=3*x+2 t=5*y+3
Statement 1:
n2=5*x n=5*x+2
Plug into nt/15: (5x+2)*(5y+3)/15
NOT SUFFICIENT > There is no way to isolate a portion that is not divisible by 15.
Statement 2:
t=3*y
Plug into nt/15:
(3x+2)(3y)/15
NOT SUFFICIENT > There is no way to isolate a portion that is not divisible by 15.
Statement 1 and 2:
(5x+2)(3y)/15 (15xy+6y)/15
If 6y/15 has a constant remainder than we can answer the question:
6*1/15 > R=6 6*2/15 > R=12 6*3/15 > R=3 6*4/15 > R=9 6*5/15 > R=0 6*6/15 > R=6 6*7/15 > R=12 6*8/15 > R=3
As you can see, the remainder is different values, but if you remember from the original problem statement. You can see that when t is divided by 5, the remainder must be 3:
6*1/15 > R=6 because 3*1/5 has R=3 6*6/15 > R=6 because 3*6/5 has R=3
Therefore the answer is C and the remainder is 6.



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Re: DS  What is the Remainder ? [#permalink]
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02 Dec 2009, 10:48
It seems that the consensus is for C being the answer. Despite this I keep getting E, and would appreciate if anyone can point out the pitfall in my reasoning:
From the stem:
\(n=3a+2\) \(a=[0, 1, 2, ..)\) \(t=5b+3\) \(b=[0, 1, 2, ..)\)
hence \(nt/15 = (3a+2)*(5b+3)/15=(15ab+9a+10b+6)/15=ab+3a/5+2b/3+2/5\) ab is always an integer, so for the purpose of the question can be neglected
I)\(n=5c+2=3a+2 a=5/3c\) \(nt/15=3/5*5/3c+2/3b+2/5=c+2/3b+2/5\) c is always an integer and can be neglected, but nothing can be said of \(2/3b+2/5\), hence NS
II) \(t=3d=5b+3\) \(b=3/5*(d1)\) \(nt/15=3/5a+2/3*3/5*(d1)+2/5=3/5a+2/5d\) \(d=[1, 2, ..)\) hence NS
I+II)\(nt/15=c+2/5d\) c is always an integer and can be neglected. \(nt/15=2/5d\) or \(nt=int+6*d\) we cannot find a single value for the remainder, hence E



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Re: DS  What is the Remainder ? [#permalink]
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16 Oct 2011, 12:07
DmitryFarber wrote: Here's more of a plain English explanation, for those who like that sort of thing. An important principle here is that you can multiply remainders. For instance, 10/7 = 1 r2 and 9/7 = 1 r3. 10*9/7 = 12 r6. See? Remainder 2 * remainder 3 = remainder 6. Notice that if the resulting remainder is greater than the dividend, it wraps around again. 10/4=2 r 2 and 15/4=3 r 3. 10*15/4 should be remainder 6, but since 4 goes into 6, there is only 2 left. The actual result is 17 r2. I think you mean the divisor, not the dividend.



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Re: DS  What is the Remainder ? [#permalink]
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16 Oct 2011, 12:58
Thanks, giantSwawn. I definitely meant divisor, not dividend. Mr. T says: "I pity the fool who can't tell the difference between a divisor and a dividend!"
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Re: How to proceed? Plug in numbers or algebra? When positive [#permalink]
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13 Nov 2011, 00:52
can some one correct me if im wrong!!
I dont think we need statements to find the reminder, question itself provide enough info..here how i solved
n=3q+2 t=5q+3  nt=15q+6
R=6




Re: How to proceed? Plug in numbers or algebra? When positive
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