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# When positive integer x is divided by positive integer y,

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Manager
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When positive integer x is divided by positive integer y, [#permalink]

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22 Sep 2006, 17:09
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15% (low)

Question Stats:

74% (01:52) correct 26% (00:48) wrong based on 168 sessions

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When positive integer x is divided by positive integer y, the remainder is 9. If x/y = 96.12, what is the value of y?

A. 96
B. 75
C. 48
D. 25
E. 12

OPEN DISCUSSION OF THIS QUESTION IS HERE: when-positive-integer-x-is-divided-by-positive-integer-y-106493.html
[Reveal] Spoiler: OA

Last edited by Bunuel on 06 Sep 2013, 00:46, edited 1 time in total.
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22 Sep 2006, 22:19
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Guys, one more simple funda.

5/2= 2.5
now .5 x2 =1 is the remainder

25/4 = 6.25
now .25x4=1 is the remainder

32/5=6.4

now.4x5 = 2 is the remainder

given x/y = 96.12 and remainder is 9

So .12 X y = 9
hence y= 75
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Last edited by cicerone on 25 Sep 2008, 01:20, edited 1 time in total.
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22 Sep 2006, 19:48
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Given x = y*m +9.
x/y = m + 9/y

or 96.12 = 96 +0.12 = m + 9/y

where m =96, and 9/y = 0.12

i.e. 9/y = 0.12

or y = 9/0.12 = 900/12 = 75.

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22 Sep 2006, 17:59
X/Y=96.12 --> Y=X/96.12 --(1)

X-Y(96.12)=9 --(2)

No solution by using (1) and (2)â€¦.

Any other approach?
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Who is John Galt?

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22 Sep 2006, 18:14
x =k*y + 9

x/y = k +9/y

96.12 - 9/y = k where k is a +ve int

So plug in vals you get B
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22 Sep 2006, 19:53
haas_mba07 wrote:
Given x = y*m +9.
x/y = m + 9/y

or 96.12 = 96 +0.12 = m + 9/y

where m =96, and 9/y = 0.12

i.e. 9/y = 0.12

or y = 9/0.12 = 900/12 = 75.

u meant B
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22 Sep 2006, 20:27
Ofcourse... B

trivikram wrote:
haas_mba07 wrote:
Given x = y*m +9.
x/y = m + 9/y

or 96.12 = 96 +0.12 = m + 9/y

where m =96, and 9/y = 0.12

i.e. 9/y = 0.12

or y = 9/0.12 = 900/12 = 75.

u meant B
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23 Sep 2006, 16:12
B, Used the same logic as cicerone

First, which value to pick?
.12 multiplied by which value gives you an integer ?
went with 75 and 25
Plugged in 75 , got remainder 9. Answer 75
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Re: When positive integer x is divided by positive integer y, [#permalink]

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06 Sep 2013, 00:46
OPEN DISCUSSION OF THIS QUESTION IS HERE: when-positive-integer-x-is-divided-by-positive-integer-y-106493.html
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Re: When positive integer x is divided by positive integer y,   [#permalink] 06 Sep 2013, 00:46
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