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Joined: 08 Jan 2013
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When the even integer n is divided by 9, the remainder is 8.
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Updated on: 25 Apr 2013, 14:36
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When the even integer n is divided by 9, the remainder is 8. Which of the following, when added to n, gives a number that is divisible by 18? A. 1 B. 4 C. 9 D. 10 E. 17 My working:
Step 1
\(\frac{n}{9}\) = x remainder 8
For example, \(\frac{17}{9}\) = 1 remainder 8 \(\frac{26}{9}\) = 2 remainder 8 \(\frac{35}{9}\) = 3 remainder 8
Therefore, n can be even or odd is a member of the set {17, 26, 35, ... }.
Step 2
Substitute the possible answers (1, 4, 9, 10, 17) to find a sum that is divisible by 18.
For example, 17 + 1 = 18, which is divisible by 18. Therefore the answer is 1 17 + 4 = 21, which is not divisible by 18 17 + 9 = 26, which is not divisible by 18 17 + 10 = 27, which is not divisible by 18 17 + 17 = 34, which is not divisible by 18
Grrr... Where did I go wrong?
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Originally posted by stormbind on 25 Apr 2013, 14:31.
Last edited by Bunuel on 25 Apr 2013, 14:36, edited 1 time in total.
Renamed the topic and edited the question.



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Re: Which sum is divisible by 18?
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25 Apr 2013, 14:33
stormbind wrote: Grrr... Where did I go wrong?
Read carefully: When the even integer n is divided by 9, the remainder is 8. Which of the following, when added to n, gives a number that is divisible by 18? 17 is not even Solution: I use real numbers here I think it's easier \(n=8\) reminder when divided by 9 is 8, to make it divisible by 18 it's easy to see that 10 is necessary \(8+10=18\) divisible by \(18\) D
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Re: When the even integer n is divided by 9, the remainder is 8.
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25 Apr 2013, 14:50
stormbind wrote: When the even integer n is divided by 9, the remainder is 8. Which of the following, when added to n, gives a number that is divisible by 18? A. 1 B. 4 C. 9 D. 10 E. 17 My working:
Step 1
\(\frac{n}{9}\) = x remainder 8
For example, \(\frac{17}{9}\) = 1 remainder 8 \(\frac{26}{9}\) = 2 remainder 8 \(\frac{35}{9}\) = 3 remainder 8
Therefore, n can be even or odd is a member of the set {17, 26, 35, ... }.
Step 2
Substitute the possible answers (1, 4, 9, 10, 17) to find a sum that is divisible by 18.
For example, 17 + 1 = 18, which is divisible by 18. Therefore the answer is 1 17 + 4 = 21, which is not divisible by 18 17 + 9 = 26, which is not divisible by 18 17 + 10 = 27, which is not divisible by 18 17 + 17 = 34, which is not divisible by 18
Grrr... Where did I go wrong? Given that \(n=9q+8\) and n is even > n could be 8, 26, 44, ... What number from answer choices when added to 8 (for example) yields a multiple of 18? 10! Answer: D. P.S. Please read and follow: rulesforpostingpleasereadthisbeforeposting133935.html Pay attention to the rule #3. Thank you.
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Re: When the even integer n is divided by 9, the remainder is 8.
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26 Oct 2018, 16:14
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Re: When the even integer n is divided by 9, the remainder is 8. &nbs
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