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When the even integer n is divided by 9, the remainder is 8.

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When the even integer n is divided by 9, the remainder is 8.  [#permalink]

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New post Updated on: 25 Apr 2013, 14:36
2
8
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

76% (00:45) correct 24% (00:36) wrong based on 245 sessions

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When the even integer n is divided by 9, the remainder is 8. Which of the following, when added to n, gives a number that is divisible by 18?

A. 1
B. 4
C. 9
D. 10
E. 17

My working:

Step 1

\(\frac{n}{9}\) = x remainder 8

For example,
\(\frac{17}{9}\) = 1 remainder 8
\(\frac{26}{9}\) = 2 remainder 8
\(\frac{35}{9}\) = 3 remainder 8

Therefore, n can be even or odd is a member of the set {17, 26, 35, ... }.

Step 2

Substitute the possible answers (1, 4, 9, 10, 17) to find a sum that is divisible by 18.

For example,
17 + 1 = 18, which is divisible by 18. Therefore the answer is 1
17 + 4 = 21, which is not divisible by 18
17 + 9 = 26, which is not divisible by 18
17 + 10 = 27, which is not divisible by 18
17 + 17 = 34, which is not divisible by 18

Grrr... Where did I go wrong?

Originally posted by stormbind on 25 Apr 2013, 14:31.
Last edited by Bunuel on 25 Apr 2013, 14:36, edited 1 time in total.
Renamed the topic and edited the question.
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Re: Which sum is divisible by 18?  [#permalink]

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New post 25 Apr 2013, 14:33
4
4
stormbind wrote:
Grrr... Where did I go wrong?


Read carefully:
When the even integer n is divided by 9, the remainder is 8. Which of the following, when added to n, gives a number that is divisible by 18?
17 is not even :wink:

Solution:

I use real numbers here I think it's easier

\(n=8\) reminder when divided by 9 is 8, to make it divisible by 18 it's easy to see that 10 is necessary
\(8+10=18\) divisible by \(18\)
D
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Re: When the even integer n is divided by 9, the remainder is 8.  [#permalink]

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New post 25 Apr 2013, 14:50
2
3
stormbind wrote:
When the even integer n is divided by 9, the remainder is 8. Which of the following, when added to n, gives a number that is divisible by 18?

A. 1
B. 4
C. 9
D. 10
E. 17

My working:

Step 1

\(\frac{n}{9}\) = x remainder 8

For example,
\(\frac{17}{9}\) = 1 remainder 8
\(\frac{26}{9}\) = 2 remainder 8
\(\frac{35}{9}\) = 3 remainder 8

Therefore, n can be even or odd is a member of the set {17, 26, 35, ... }.

Step 2

Substitute the possible answers (1, 4, 9, 10, 17) to find a sum that is divisible by 18.

For example,
17 + 1 = 18, which is divisible by 18. Therefore the answer is 1
17 + 4 = 21, which is not divisible by 18
17 + 9 = 26, which is not divisible by 18
17 + 10 = 27, which is not divisible by 18
17 + 17 = 34, which is not divisible by 18

Grrr... Where did I go wrong?


Given that \(n=9q+8\) and n is even --> n could be 8, 26, 44, ...

What number from answer choices when added to 8 (for example) yields a multiple of 18? 10!

Answer: D.

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Re: When the even integer n is divided by 9, the remainder is 8.  [#permalink]

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New post 26 Oct 2018, 16:14
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Re: When the even integer n is divided by 9, the remainder is 8. &nbs [#permalink] 26 Oct 2018, 16:14
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When the even integer n is divided by 9, the remainder is 8.

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