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When the positive integer x is divided by 11, the quotient  [#permalink]

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When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also 3. What is the remainder when y is divided by 19?

A. 0
B. 1
C. 2
D. 3
E. 4

Guys struggling to solve this. But this is the concept I am trying to apply:

We can extrapolate a general statement from this form. When dividing x by y, the quotient is q and the remainder is r:
x/y = q + r/y

From there, we can solve for x:
x = qy + r (thats the general form of x = 3(integer) + 1)
Or the quotient:
q = x-r/y

Or, even, the remainder itself:
r = x - qy

But I am getting stuck in finding y when x is divided by 19. Can someone please help?? I don't have an OA either.

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Re: Quotient and Remainder  [#permalink]

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25
15
enigma123 wrote:
When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also 3. What is the remainder when y is divided by 19?

A) 0
B) 1
C) 2
D) 3
E) 4

If you decide to go with quotient/remainder formula approach, then I'd suggest to express the info in the stem with it. And then look whether we can somehow manipulate with the expressions at hand to answer the question.

(1) When the positive integer x is divided by 11, the quotient is y and the remainder 3 --> $$x=11y+3$$;
(2) When x is divided by 19, the remainder is also 3 --> $$x=19q+3$$.

Easy to spot that $$19q+3=11y+3$$ --> $$19q=11y$$ --> $$y=\frac{19q}{11}$$. Now as $$y$$ and $$q$$ are integers and 19 is prime then $$\frac{q}{11}$$ must be an integer --> $$y=19*integer$$ --> $$y$$ is a multiple of 19, hence when divide by 19 remainder is 0.

Hope its clear.
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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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6
1
enigma123 wrote:
When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also 3. What is the remainder when y is divided by 19?

A. 0
B. 1
C. 2
D. 3
E. 4

Guys struggling to solve this. But this is the concept I am trying to apply:

We can extrapolate a general statement from this form. When dividing x by y, the quotient is q and the remainder is r:
x/y = q + r/y

From there, we can solve for x:
x = qy + r (thats the general form of x = 3(integer) + 1)
Or the quotient:
q = x-r/y

Or, even, the remainder itself:
r = x - qy

But I am getting stuck in finding y when x is divided by 19. Can someone please help?? I don't have an OA either.

Take LCM of 19 & 11 = 209
Adding 3 = 212
Say x = 212

212/11: Quotient = 19 (=y) & remainder = 3

212/19: Quotient = 11 & remainder = 3

19/19: Quotient = 1 & remainder = 0 = Answer = A
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GMAT 1: 770 Q50 V46 Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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2
Find some numbers that fit the question.

We are told that x and y both give a remainder of 3 when divided by 19 or 11.

We can easily construct a number that fits this.

x = 19*11 + 3

x / 11 = 19 + 3 / 19

so y = 19

remainder when y / 19 is 0

A
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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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enigma123 wrote:
When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also 3. What is the remainder when y is divided by 19?

A. 0
B. 1
C. 2
D. 3
E. 4

Sol: Given x=11y+3 or y= (x-3)/11
Also x=19a+3 Substitute for x in the above equation we get

y= (19a+3-3)/11 or y=19a/11. Note that "a" is an integer and multiple of 11

y/19 =a/11 where a/11 is an integer and hence remainder is 0

Ans is A
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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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1
Such questions are disaster as they take a lot of time solving. but here is a shorter way i.e through equations.
x/ 11 yields remainder 3 and quotient y. so we can form equation

x= 11y + 3 ........(1)

also we know that when x is divided by 19, remainder is same. let's take "a" as a quotient.

x=19a +3 .........(2)
equating 1 and 2
11y+3= 19a+3
11y=19a

since both 19 and 11 are prime numbers, with no number in common, so the only values a and y can get are
y=19 and a=11

y/19 =19/19 remainder =0

hope it helps.
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GMAT 1: 800 Q51 V49 GRE 1: Q170 V170 Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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Hi All,

We're told that...
X/11 = Y remainder 3
X/19 = something remainder 3

With the first piece of information, we know that X is 3 greater than a multiple of 11; with the second piece of information, we know that X is 3 greater than a multiple of 19. To have a remainder of 3 when you divide X by BOTH 11 and 19, X must be a number that is 3 greater than a MULTIPLE of BOTH 11 and 19.

We're asked what the remainder would be when Y is divided by 19. At this point, you might recognize that you could choose Y=19 and solve from there. If you don't recognize why that that relationship exists, then here's a more step-heavy way to get to the correct answer:

X = (11)(19) + 3 = 209 + 3 = 212

212/11 = Y remainder 3
212 = 11Y + 3
209 = 11Y
209/11 = Y
19 = Y

We're ultimately asked what the remainder would be when 19 is divided by 19. The remainder is 0.

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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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1
Top Contributor
enigma123 wrote:
When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also 3. What is the remainder when y is divided by 19?

A. 0
B. 1
C. 2
D. 3
E. 4

A fast approach is to find a value of x that meets the given conditions.

When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also 3....
Notice that x = 3 meets the above conditions.
3 divided by 11 = 0 with remainder 3. In this case, y = 0
Likewise, 3 divided by 11 also leaves a remainder of 3

What is the remainder when y is divided by 19?
In the above example, y = 0
So, when we divide 0 by 19, the remainder is 0

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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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Can we argue that this is a poorly written question? I was always taught that the quotient was the result of division. At first I paused thinking they must mean just the integer, even though I'd never seen that definition used. Then I decided that must be the "trick" of the question, that y is in fact the answer to x/11.

I got

x = 212

y = 19 + 3/11 = 212/11

y/19 = 212/11 * 1/19 = 212/209 = 1 R 3

The trick would be that people would misinterpret the question and mistake y as 19. But if y is x/11, then we will only have the same remainder when x is a multiple of 19 and 11. (Multiple of 19) + 3 yields a remainder of 3 when 19 is the divisor. Basically, the question would be testing only logic and, in theory, you would never have to figure out any values at all.

So I input the answer as 3, which is not the OA.

Afterward, I looked it up and quotient can also refer to just the integer of the result.

My question: Would this ever be a real GMAT question? We are taught (at least in American schools) that quotient is not just integer, but integer and remainder. Thus, the question appears ambiguous to me and probably a large segment of other GMAT takers. Thoughts?

Edit:

Just consulted OG: "For example, when 28 is divided by 8, the quotient is 3 and the remainder is 4 since 28 = (8)(3) + 4" (p. 108). OG for GRE says something similar. I just find it bizarre that at no time in my formal education did anyone give this definition.
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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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x=11y+3 and x=19z+3

11y+3=19z+3 => 11y=19z => y/z=19/11

It means that y is a multiple of 19, so when we divide y by 19 we will have r=0

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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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enigma123 wrote:
When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also 3. What is the remainder when y is divided by 19?

A. 0
B. 1
C. 2
D. 3
E. 4

Guys struggling to solve this. But this is the concept I am trying to apply:

We can extrapolate a general statement from this form. When dividing x by y, the quotient is q and the remainder is r:
x/y = q + r/y

From there, we can solve for x:
x = qy + r (thats the general form of x = 3(integer) + 1)
Or the quotient:
q = x-r/y

Or, even, the remainder itself:
r = x - qy

But I am getting stuck in finding y when x is divided by 19. Can someone please help?? I don't have an OA either.

Please find the solution as attached,
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When the positive integer x is divided by 11, the quotient  [#permalink]

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When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also 3. What is the remainder when y is divided by 19?

A) 0
B) 1
C) 2
D) 3
E) 4

least value of x=3
3/11 gives a quotient of 0
y=0
0/19 leaves a remainder of 0
A

Originally posted by gracie on 29 Aug 2016, 12:14.
Last edited by gracie on 26 Jan 2018, 19:11, edited 1 time in total.
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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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A is the correct answer. Here's why:

From the prompt we can derive two equations:

x=11y+3
x=19z+3

From this we can set the two equal to each other, leaving us with...

11y=19z --> manipulate further to give... 11 = (19z)/y --> From this we know that z must equal 11 and y must equal 19 in order for the equation to hold. Therefore, since y = 19, dividing by 19 will give a remainder of 0
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GRE 1: Q169 V154 When the positive integer x is divided by 11, the quotient  [#permalink]

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Hey Everyone.
There are two methods that can be used here as far as i know.

First =>
x=11y+3
and x=19z+3
for some integer z
Hence 11y+3=19z+3
11y=19z
=> z=11y/19
as z needs to be an integer => y must be a multiple of 19.
Hence the remainder that y leaves with 19 must be zero.

Second =>
You see this is a problem solving question.
We will have only one answer.

x=19y+3
x=11z+3
hence combing the equations => x= 3+11*19*p for some integer p.
smallest possible value of x is 3
for the y is zero.
so y=0 is a acceptable value.
what is the remainder when 0 is divided by 19 ?
Its zero.
as every number divides 0.
Hence the answer must be zero.

Hence Zero is the answer.
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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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enigma123 wrote:
When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also 3. What is the remainder when y is divided by 19?

A. 0
B. 1
C. 2
D. 3
E. 4

19z + 3 = x = 11y + 3

Or, x = 19*11 + 3 { z = 11 and y = 19 }

or, x = 202

y/19 = Quotient 1 and remainder 0

Hence , answer will be (A) 0

Hope this helps !!

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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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Bunuel wrote:
enigma123 wrote:
When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also 3. What is the remainder when y is divided by 19?

A) 0
B) 1
C) 2
D) 3
E) 4

If you decide to go with quotient/remainder formula approach, then I'd suggest to express the info in the stem with it. And then look whether we can somehow manipulate with the expressions at hand to answer the question.

(1) When the positive integer x is divided by 11, the quotient is y and the remainder 3 --> $$x=11y+3$$;
(2) When x is divided by 19, the remainder is also 3 --> $$x=19q+3$$.

Easy to spot that $$19q+3=11y+3$$ --> $$19q=11y$$ --> $$y=\frac{19q}{11}$$. Now as $$y$$ and $$q$$ are integers and 19 is prime then $$\frac{q}{11}$$ must be an integer --> $$y=19*integer$$ --> $$y$$ is a multiple of 19, hence when divide by 19 remainder is 0.

Hope its clear.

Bunuel, what is the relationship between prime and divider in this case?
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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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ziyuenlau wrote:
Bunuel wrote:
enigma123 wrote:
When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also 3. What is the remainder when y is divided by 19?

A) 0
B) 1
C) 2
D) 3
E) 4

If you decide to go with quotient/remainder formula approach, then I'd suggest to express the info in the stem with it. And then look whether we can somehow manipulate with the expressions at hand to answer the question.

(1) When the positive integer x is divided by 11, the quotient is y and the remainder 3 --> $$x=11y+3$$;
(2) When x is divided by 19, the remainder is also 3 --> $$x=19q+3$$.

Easy to spot that $$19q+3=11y+3$$ --> $$19q=11y$$ --> $$y=\frac{19q}{11}$$. Now as $$y$$ and $$q$$ are integers and 19 is prime then $$\frac{q}{11}$$ must be an integer --> $$y=19*integer$$ --> $$y$$ is a multiple of 19, hence when divide by 19 remainder is 0.

Hope its clear.

Bunuel, what is the relationship between prime and divider in this case?

We have $$y=\frac{19q}{11}$$. 19 is not a multiple of 11, thus for 19q/11 to be an integer q must be a multiple of 11.
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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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enigma123 wrote:
When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also 3. What is the remainder when y is divided by 19?

A. 0
B. 1
C. 2
D. 3
E. 4

3+(11*19)=212=x
212/11 gives a quotient of 19=y
19/19 leaves a remainder of 0
A
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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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enigma123 wrote:
When the positive integer x is divided by 11, the quotient is y and the remainder 3. When x is divided by 19, the remainder is also 3. What is the remainder when y is divided by 19?

A. 0
B. 1
C. 2
D. 3
E. 4

We can create the following expressions:

x = 11y + 3

and

x = 19Q + 3

Thus:

11y + 3 = 19Q + 3

11y = 19Q

11y/19 = Q

Since Q is an integer and 11 is not divisible by 19, then y must be divisible by 19, and hence the remainder when y is divided by 19 is zero.

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Re: When the positive integer x is divided by 11, the quotient  [#permalink]

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