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# When the price of oranges is lowered by 40%, 4 more oranges

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Manager
Joined: 15 Apr 2012
Posts: 93

Kudos [?]: 60 [0], given: 134

Concentration: Technology, Entrepreneurship
GMAT 1: 460 Q38 V17
GPA: 3.56
When the price of oranges is lowered by 40%, 4 more oranges [#permalink]

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08 Jul 2012, 06:19
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Difficulty:

35% (medium)

Question Stats:

71% (02:02) correct 29% (02:26) wrong based on 84 sessions

When the price of oranges is lowered by 40%, 4 more oranges can be purchased for $12 than can be purchased for the original price. How many oranges can be purchased for 24 dollars at the original price? (A) 8 (B) 12 (C) 16 (D) 20 (E) 24 [Reveal] Spoiler: OA Last edited by Bunuel on 08 Jul 2012, 06:22, edited 1 time in total. Edited the question. Kudos [?]: 60 [0], given: 134 Math Expert Joined: 02 Sep 2009 Posts: 41871 Kudos [?]: 128551 [1], given: 12180 Re: When the price of oranges is lowered by 40%, 4 more oranges [#permalink] ### Show Tags 08 Jul 2012, 06:33 1 This post received KUDOS Expert's post farukqmul wrote: When the price of oranges is lowered by 40%, 4 more oranges can be purchased for$12 than can be purchased for the original price. How many oranges can be purchased for 24 dollars at the original price?

(A) 8
(B) 12
(C) 16
(D) 20
(E) 24

Say $$x$$ is the original price of an orange, then:

$$xn=12$$;
and
$$0.6x*(n+4)=12$$ --> $$x(n+4)=20$$ --> $$xn+4x=20$$ --> $$12+4x=20$$ --> $$x=2$$.

So, for 24 dollars 24/2=12 oranges can be purchased at the original price of $2. Answer: B. _________________ Kudos [?]: 128551 [1], given: 12180 Intern Joined: 26 May 2012 Posts: 25 Kudos [?]: 16 [0], given: 10 Re: When the price of oranges is lowered by 40%, 4 more oranges [#permalink] ### Show Tags 15 Jul 2012, 03:22 Bunuel wrote: farukqmul wrote: When the price of oranges is lowered by 40%, 4 more oranges can be purchased for$12 than can be purchased for the original price. How many oranges can be purchased for 24 dollars at the original price?

(A) 8
(B) 12
(C) 16
(D) 20
(E) 24

Say $$x$$ is the original price of an orange, then:

$$xn=12$$;
and
$$0.6x*(n+4)=12$$ --> $$x(n+4)=20$$ --> $$xn+4x=20$$ --> $$12+4x=20$$ --> $$x=2$$.

So, for 24 dollars 24/2=12 oranges can be purchased at the original price of $2. Answer: B. are there any other ways? Kudos [?]: 16 [0], given: 10 Senior Manager Status: DONE! Joined: 05 Sep 2016 Posts: 408 Kudos [?]: 23 [0], given: 283 Re: When the price of oranges is lowered by 40%, 4 more oranges [#permalink] ### Show Tags 22 Oct 2016, 12:32 Set up: 12/p = x 12/0.60 = x+4 Manipulate and plug the first equation into the second --> you'll find p =$2

Thus $24/$2 per orange = 12 oranges

Kudos [?]: 23 [0], given: 283

Director
Joined: 07 Dec 2014
Posts: 810

Kudos [?]: 247 [0], given: 12

Re: When the price of oranges is lowered by 40%, 4 more oranges [#permalink]

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22 Oct 2016, 18:22
farukqmul wrote:
When the price of oranges is lowered by 40%, 4 more oranges can be purchased for $12 than can be purchased for the original price. How many oranges can be purchased for 24 dollars at the original price? (A) 8 (B) 12 (C) 16 (D) 20 (E) 24 let r=number of oranges purchased originally [12/(r+4)]/(12/r)=.6 r/(r+4)=.6 r=6 oranges$12/6=$2 per orange$24/$2=12 oranges B Kudos [?]: 247 [0], given: 12 BSchool Forum Moderator Joined: 12 Aug 2015 Posts: 2212 Kudos [?]: 836 [0], given: 595 Re: When the price of oranges is lowered by 40%, 4 more oranges [#permalink] ### Show Tags 21 Apr 2017, 01:28 Here is what i did in this question => Let the price of each orange be$x
Hence for $12 => we can buy => 12/x oranges Now new price => x(1-40/100) =>$0.6x
Hence for $12 we could now buy => 12/0.6x As per the given information => 12/x+4=12/0.6x Hence 12+4x/x=20/x => 12+4x=20 =>x=2 So the price of each orange is$2

Now for 24 dollars => we can buy => 1/2*24=12 oranges

SMASH THAT B.

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Kudos [?]: 836 [0], given: 595

Re: When the price of oranges is lowered by 40%, 4 more oranges   [#permalink] 21 Apr 2017, 01:28
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