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Which number in set A has a value greater than that of every

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Which number in set A has a value greater than that of every [#permalink]

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09 May 2004, 10:57
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Which number in set A has a value greater than that of every other number of set A, if all members of set A are negative numbers.

1. every member of set A is the product of -1 and a prime number
2. at least one member of A is even
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09 May 2004, 11:54
B is sufficient ( since 0 is not a -ve number ) only -2 is even -ve prime number.
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09 May 2004, 23:39
i agree with B..
for the same reasons
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10 May 2004, 10:31
Quote:

B states that atleast one number in set A is even.
Consider following two possibilities for A
A={-16,-3,-,-17) this set has at least one even negative number, however it may not be the greatest. another possibility (A={-2,-3,-1} we get two answers. Hence insufficient.

Statement A states that set is a set of prime numbers multuplied by -1
so A={-2,-3,-7,....} or A={-3,-4,-5} hence insufficient.

Combine the two, we get answer -2 as the only even prime number is 2.

Please correct if I am wrong.

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10 May 2004, 10:34
C it is.

1 does not tell whether -2 included in the set or not.
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10 May 2004, 10:47
its C , same reason as hallelujah1234
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10 May 2004, 11:18
Opps I realize the mistake I though the set contained only prime numbers to begin with.
I agree it is C.
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10 May 2004, 11:25
hmmmmmmmmmmmm

i see....and I agree..thanks for pointing out my errors
10 May 2004, 11:25
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