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Which of the follow is a set of all possible values of y that satisfy

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Re: Which of the follow is a set of all possible values of y that satisfy [#permalink]
Alhamdan1995 wrote:
$$y-13\sqrt{y}+36 = 0$$

A) (2,3)
B) (+/-2,+/-3)
C) (4,9)
D) (-4,-9)
E) (16,81)

$$y−13\sqrt{y}+36=0$$

Let $$\sqrt{y} = x$$ => $$y=x^2$$

$$x^2−13x+36=0$$
(x-9)(x-4)=0
x = 9 or x = 4

Therefore,
[m]\sqrt{y} = 9 => y = 81
[m]\sqrt{y} = 4 => y = 16

y = 16,81

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Re: Which of the follow is a set of all possible values of y that satisfy [#permalink]
Alhamdan1995 wrote:
$$y-13\sqrt{y}+36 = 0$$

A) (2,3)
B) (+/-2,+/-3)
C) (4,9)
D) (-4,-9)
E) (16,81)

$$y-13\sqrt{y}+36 = 0$$
$$\sqrt{y}$$=4 or 9
y = 16 or 81
Hence, OA is (E).
Re: Which of the follow is a set of all possible values of y that satisfy [#permalink]
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