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# Which of the following is a solution for the above equation

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Manager
Joined: 11 Dec 2013
Posts: 121
Location: India
GMAT Date: 03-15-2015
WE: Education (Education)
Which of the following is a solution for the above equation  [#permalink]

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28 Feb 2019, 22:23
2
00:00

Difficulty:

85% (hard)

Question Stats:

48% (02:54) correct 52% (02:39) wrong based on 52 sessions

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$$|x+2|+|2x+6|+|3x-3|=12$$
Which of the following is a solution for the above equation

A) $$-\frac{5}{2}$$

B) $$-\frac{7}{5}$$

C) $$-\frac{7}{6}$$

D) $$\frac{5}{6}$$

E) $$\frac{5}{3}$$

Source : Ignus

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Joined: 18 Jul 2018
Posts: 1019
Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)
Which of the following is a solution for the above equation  [#permalink]

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01 Mar 2019, 09:55
Let us substitute options and check.

From 1) x = -5/2
Put this in the question.
$$|\frac{-5}{2}+1|+|2(\frac{-5}{2})+6|+|3(\frac{-5}{2})-3|$$

$$|\frac{1}{2}+1+\frac{21}{2}|$$

$$12$$

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Joined: 02 Dec 2018
Posts: 15
Re: Which of the following is a solution for the above equation  [#permalink]

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04 Mar 2019, 13:19
Chethan92 wrote:
Let us substitute options and check.

From 1) x = -5/2
Put this in the question.
$$|\frac{-5}{2}+1|+|2(\frac{-5}{2})+6|+|3(\frac{-5}{2})-3|$$

$$|\frac{1}{2}+1+\frac{21}{2}|$$

$$12$$

Is there an efficient way to solve without plugging in values?
NUS School Moderator
Joined: 18 Jul 2018
Posts: 1019
Location: India
Concentration: Finance, Marketing
WE: Engineering (Energy and Utilities)
Re: Which of the following is a solution for the above equation  [#permalink]

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05 Mar 2019, 09:45
goobo wrote:
Chethan92 wrote:
Let us substitute options and check.

From 1) x = -5/2
Put this in the question.
$$|\frac{-5}{2}+1|+|2(\frac{-5}{2})+6|+|3(\frac{-5}{2})-3|$$

$$|\frac{1}{2}+1+\frac{21}{2}|$$

$$12$$

Is there an efficient way to solve without plugging in values?

goobo, As there are 3 mods. the number of equations you get is more and it becomes difficult to solve it under 2 minutes.
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Re: Which of the following is a solution for the above equation   [#permalink] 05 Mar 2019, 09:45
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