bgbeidas wrote:
=>\((\sqrt{2}*\sqrt[3]{3})^3\)
=> \(2\sqrt{2}*3 = 6\sqrt{2}\)
C
I understand how you got 3, and how you should gt 2\sqrt{2} at the bottom.
But the 2 in the top part, when I cube it I get 8, not sure where that disappears in your process.
I think u are clear with this part =>\((\sqrt{2}*\sqrt[3]{3})^3\)
=>\((\sqrt{2}*\sqrt[3]{3})^3\)
=> (\(2^{1/2}\) * \(3^{1/3}\))\(^{3}\)
=> \(2^{3/2}\)* \(3^{3/3}\)
=>
\(2^1\)* \(2^{1/2}\)*
\(3^1\) { Because \(\frac{3}{2}\) = \(1 \frac{1}{2}\) and
\(\frac{3}{3}\) = 1 }=> \(2^1\)* \(2^{1/2}\)* \(3^1\)
=> 2*\(\sqrt{2}\) * 3
=>6\(\sqrt{2}\)
Hope this helps !! 
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