antarcticsugar wrote:

MathRevolution wrote:

=>

x! / ( x + 1 )! + ( x + 1 )! / ( x + 2 )!

= x! / {x! * (x+1)} + (x+1)! / { (x+1)! * (x+2) }

= 1/(x+1) + 1/(x+2) = (2x+3)/(x+1)(x+2)

Therefore, C is the answer.

Answer: C

HI, how did you get this?

x! / {x! * (x+1)}

Well x! means= x*(x-1)*(x-2)*.....(x-x)

Well treat it like this when you write 4! what does it means??

It means 4x3x2x1 and we know that 3! = 3x2x1

so 4! = 4* 3!

Hope it is clear..

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