November 17, 2018 November 17, 2018 07:00 AM PST 09:00 AM PST Nov. 17, 7 AM PST. Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT. November 17, 2018 November 17, 2018 09:00 AM PST 11:00 AM PST Join the Quiz Saturday November 17th, 9 AM PST. The Quiz will last approximately 2 hours. Make sure you are on time or you will be at a disadvantage.
Author 
Message 
TAGS:

Hide Tags

CEO
Joined: 20 Mar 2014
Posts: 2635
Concentration: Finance, Strategy
GPA: 3.7
WE: Engineering (Aerospace and Defense)

Re: 'Work' Word Problems Made Easy
[#permalink]
Show Tags
30 Jul 2015, 08:38
JRAppz wrote: Can someone help with this question? If it takes 4 machines, working at the same constant rate, 2 hours to complete 2 jobs, how long will it take 3 machines, working at the same constant rate, to complete 3 jobs?"
The answer is 4 hours but I have no idea how to arrive at the answer, hopefully someone can help. You can follow the method mentioned by Bunuel above . The only thing you need to remember is that the work rate problems are similar to distancespeedtime wherein Distance is similar to job, speed is similar to rate and time is constant. Thus, as distance = speed X time Job or work = rate x time Additionally, as with more machines, the total time required will reduce for the same amount of work, combined rates of 'n' machines will be n*rate of 1 machine.



CEO
Status: GMATINSIGHT Tutor
Joined: 08 Jul 2010
Posts: 2700
Location: India
GMAT: INSIGHT
WE: Education (Education)

Re: 'Work' Word Problems Made Easy
[#permalink]
Show Tags
30 Jul 2015, 09:27
JRAppz wrote: Can someone help with this question? If it takes 4 machines, working at the same constant rate, 2 hours to complete 2 jobs, how long will it take 3 machines, working at the same constant rate, to complete 3 jobs?"
The answer is 4 hours but I have no idea how to arrive at the answer, hopefully someone can help. CONCEPT: \(\frac{(Machine_Power * Time)}{Work} = Constant\)i.e. \(\frac{(M_1 * T_1)}{W_1} = \frac{(M_2 * T_2)}{W_2}\) i.e. \(\frac{(4 * 2))}{2} = \frac{(3 * T_2)}{3}\) i.e. \(T_2 = 4\)
_________________
Prosper!!! GMATinsight Bhoopendra Singh and Dr.Sushma Jha email: info@GMATinsight.com I Call us : +919999687183 / 9891333772 Online OneonOne Skype based classes and Classroom Coaching in South and West Delhi http://www.GMATinsight.com/testimonials.html
ACCESS FREE GMAT TESTS HERE:22 ONLINE FREE (FULL LENGTH) GMAT CAT (PRACTICE TESTS) LINK COLLECTION



Current Student
Joined: 12 Aug 2015
Posts: 287
Concentration: General Management, Operations
GMAT 1: 640 Q40 V37 GMAT 2: 650 Q43 V36 GMAT 3: 600 Q47 V27
GPA: 3.3
WE: Management Consulting (Consulting)

Re: 'Work' Word Problems Made Easy
[#permalink]
Show Tags
02 Jan 2016, 06:03
hi can anyone help me with this concept please? i get confused why concept employed in Bunuel's example contradicts with the example given in this thread? m30184568.html#p1618937
_________________
KUDO me plenty



Manager
Joined: 03 May 2014
Posts: 161
Location: India
WE: Sales (Mutual Funds and Brokerage)

'Work' Word Problems Made Easy
[#permalink]
Show Tags
20 Mar 2016, 00:13
rainbooow wrote: sriharimurthy wrote: ‘Work’ Word Problems Made Easy
We are told that B produces 10% more sprockets per hour than A, thus \(\frac{660}{t+10}*1.1=\frac{660}{t}\) > \(t=100\) > the rate of A is \(\frac{660}{t+10}=6\) sprockets per hour.
Can someone explain to me how to get t=100? from this equation? Thank you! 660/(t+10)X1.1=660/t Multiply 660 by 1.1 you get 726. The equation becomes 726/(t+10)=660/t Now cross multiply the equation 726t=660t+6600 726t660t=66T. so the equation takes the form 66t=6600 or t= 6600/66= 100



Intern
Joined: 05 May 2016
Posts: 6
Location: India

Re: 'Work' Word Problems Made Easy
[#permalink]
Show Tags
09 May 2016, 11:59
example 4 =Machine A and Machine B are used to manufacture 660 sprockets. It takes machine A ten hours longer to produce 660 sprockets than machine B. Machine B produces 10% more sprockets per hour than machine A. How many sprockets per hour does machine A produce? in this question solution We are told that B produces 10% more sprockets per hour than A, thus 660t+10∗1.1=660t660t+10∗1.1=660t > t=100t=100 > the rate of A is 660t+10=6660t+10=6 sprockets per hour.
how did 1.1 come ..plz help



Intern
Joined: 22 Jun 2016
Posts: 7

Re: 'Work' Word Problems Made Easy
[#permalink]
Show Tags
02 Oct 2016, 04:43
sondenso wrote: JoyLibs wrote: Can someone help me solve this DS problem on 'Work'
A group of 5 craftsmen, working together at the same rate, can finish a job in 3 hours. How long will it take a group of 4 apprentices working together to do the same job?
(1) Each apprentice works at 2/3 the rate of a craftsman. (2) The 5 craftsmen and the 4 apprentices working together will take 45/23 hours to finish the job. x= time 4 apprentices need to do a job and what is x? 1. 1/(3*5) = (2/3)* {1/(4*x)}>x is specific. suff 2. 1/(3*5) + 1/(4*x) = 23/45 >x is specific, suff D I am just wondering shoudn't the first statement be be (2/3)*1/(3*5)={1/(4*x)} ?



Manager
Joined: 13 Dec 2013
Posts: 158
Location: United States (NY)
Concentration: Nonprofit, International Business
GMAT 1: 710 Q46 V41 GMAT 2: 720 Q48 V40
GPA: 4
WE: Consulting (Consulting)

Re: 'Work' Word Problems Made Easy
[#permalink]
Show Tags
23 Mar 2017, 21:30
JoyLibs wrote: Can someone help me solve this DS problem on 'Work'
A group of 5 craftsmen, working together at the same rate, can finish a job in 3 hours. How long will it take a group of 4 apprentices working together to do the same job?
(1) Each apprentice works at 2/3 the rate of a craftsman. (2) The 5 craftsmen and the 4 apprentices working together will take 45/23 hours to finish the job. From stem: 5(1/C)=1/3, where C is the number hours taken by one craftsman to complete the job. 1/C=1/15, so each craftsman takes 15h to complete the job. 1) (2/3)*(1/15)=2/45=rate of one apprentice rate of 4 apprentices is therefore 8/45. The apprentices take 45/8 h. Suff. 2) 5(1/C) + 4(1/A) = 23/45 1/3 + 4/A = 23/45 4/A= 23/45  1/3 = 69/135  45/135 = 24/135 = 8/45 = 45/8 h Suff.



SVP
Joined: 12 Dec 2016
Posts: 1674
Location: United States
GPA: 3.64

Re: 'Work' Word Problems Made Easy
[#permalink]
Show Tags
13 May 2017, 14:35
some quantitative questions asks to find the total least amount of time, can sb pls help me with this, thanks. For example, if A starts every 30 min, and it takes 1h20 to finish ride A. B starts every 45 min, and it takes 50 min to fnish ride B ....... what is the least total amount of time?
How to solve this question in less than 2 min???



Intern
Joined: 04 Aug 2014
Posts: 3

'Work' Word Problems Made Easy
[#permalink]
Show Tags
09 Mar 2018, 00:26
rainbooow wrote: sriharimurthy wrote: ‘Work’ Word Problems Made Easy
We are told that B produces 10% more sprockets per hour than A, thus \(\frac{660}{t+10}*1.1=\frac{660}{t}\) > \(t=100\) > the rate of A is \(\frac{660}{t+10}=6\) sprockets per hour.
Can someone explain to me how to get t=100? from this equation? Thank you! Bumping this question up: How do we quickly solve 660/(t+10)*1.1=660/t > t=100? I understand we can multiply both sides by t(t+10) to get rid of the denominators, but solving this way involves some serious computations (which I would take me several minutes, I'm afraid...). Is there a faster way?



Intern
Joined: 03 Feb 2016
Posts: 13
Location: China

Re: 'Work' Word Problems Made Easy
[#permalink]
Show Tags
09 Sep 2018, 19:10
Ziggygee11  I think the Answer to your question is 24. This is how i solved it: 40/t+4 + 40/t = 50/6 Solving this you get t =8 So A' rate = 10/3 For 80 pages it will be 80*3/10 = 24



VP
Joined: 09 Mar 2016
Posts: 1076

'Work' Word Problems Made Easy
[#permalink]
Show Tags
29 Sep 2018, 06:09
sriharimurthy wrote:
Example 3. Working together, printer A and printer B would finish a task in 24 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 5 pages a minute more than printer A?
Solution: This problem is interesting because it tests not only our knowledge of the concept of word problems, but also our ability to ‘translate English to Math’
‘Working together, printer A and printer B would finish a task in 24 minutes’ This tells us that A and B combined would work at the rate of \(\frac{1}{24}\) per minute.
‘Printer A alone would finish the task in 60 minutes’ This tells us that A works at a rate of \(\frac{1}{60}\) per minute.
At this point, it should strike you that with just this much information, it is possible to calculate the rate at which B works: Rate at which B works = \(\frac{1}{24}\frac{1}{60}=\frac{1}{40}\).
‘B prints 5 pages a minute more than printer A’ This means that the difference between the amount of work B and A complete in one minute corresponds to 5 pages. So, let us calculate that difference. It will be \(\frac{1}{40}\frac{1}{60}=\frac{1}{120}\)
‘How many pages does the task contain?’ If \(\frac{1}{120}\) of the job consists of 5 pages, then the 1 job will consist of \(\frac{(5*1)}{\frac{1}{120}} = 600\) pages.
pushpitkc, Bunuel VeritasKarishma if in denominator always is given time (unless is reversed ) \(\frac{1}{120}\) then how can 120 be amount of work ? what does 5*1 mean ? and why are we dividing by 1/120 to get WORK DONE as per FORMULA > WORK = RATE * TIME pls explain



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 8540
Location: Pune, India

Re: 'Work' Word Problems Made Easy
[#permalink]
Show Tags
01 Oct 2018, 02:41
dave13 wrote: sriharimurthy wrote:
Example 3. Working together, printer A and printer B would finish a task in 24 minutes. Printer A alone would finish the task in 60 minutes. How many pages does the task contain if printer B prints 5 pages a minute more than printer A?
Solution: This problem is interesting because it tests not only our knowledge of the concept of word problems, but also our ability to ‘translate English to Math’
‘Working together, printer A and printer B would finish a task in 24 minutes’ This tells us that A and B combined would work at the rate of \(\frac{1}{24}\) per minute.
‘Printer A alone would finish the task in 60 minutes’ This tells us that A works at a rate of \(\frac{1}{60}\) per minute.
At this point, it should strike you that with just this much information, it is possible to calculate the rate at which B works: Rate at which B works = \(\frac{1}{24}\frac{1}{60}=\frac{1}{40}\).
‘B prints 5 pages a minute more than printer A’ This means that the difference between the amount of work B and A complete in one minute corresponds to 5 pages. So, let us calculate that difference. It will be \(\frac{1}{40}\frac{1}{60}=\frac{1}{120}\)
‘How many pages does the task contain?’ If \(\frac{1}{120}\) of the job consists of 5 pages, then the 1 job will consist of \(\frac{(5*1)}{\frac{1}{120}} = 600\) pages.
pushpitkc, Bunuel VeritasKarishma if in denominator always is given time (unless is reversed ) \(\frac{1}{120}\) then how can 120 be amount of work ? what does 5*1 mean ? and why are we dividing by 1/120 to get WORK DONE as per FORMULA > WORK = RATE * TIME pls explain Imp: Ensure that you always have your eye on the units. When you are flipping a quantity, know why. A and B finish a task in 24 mins. If work done has to be 1 (complete work), their rate of work is (1/24)th of the work per min. (It is usually the case that we consider work to be 1 work) Work = Rate*Time 1 work = Rate* 24 mins Rate = (1/24)th of work per min Similarly, A's rate of work = (1/60)th of work per min Since rates are additive, we get that B's rate must be (1/40)th of work per min. So B does (1/40)th of the work in a min while B does only (1/60)th of the work. We are given that this difference of (1/40)th work and (1/60)th work is 5 pages. So 1 complete work is 600 pages. Now the rate of work can be expressed in terms of pages/min too. B prints (1/40)*600 = 15 pages/min A prints (1/60)*600 = 10 pages/min
_________________
Karishma Veritas Prep GMAT Instructor
Learn more about how Veritas Prep can help you achieve a great GMAT score by checking out their GMAT Prep Options >
GMAT selfstudy has never been more personalized or more fun. Try ORION Free!




Re: 'Work' Word Problems Made Easy &nbs
[#permalink]
01 Oct 2018, 02:41



Go to page
Previous
1 2 3
[ 52 posts ]



