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14 May 2017, 10:58
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C
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Working together, Jeff and Ashley painted their apartment in 6 hours. If Jeff had been working alone, he could have painted the whole apartment in 10 hours. How many hours would it have taken Ashley to paint the apartment alone?
A. 4
B. 12
C. 15
D. 16
E. 20
A. 4
B. 12
C. 15
D. 16
E. 20
15 May 2017, 01:23
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Let the no of hours taken by Ashley= A
Work done by all of them in 1 hour is given by following equation:
\(\frac{1}{10}\)+\(\frac{1}{A}\)= \(\frac{1}{6}\)
\(\frac{1}{A}\)= \(\frac{1}{6}\)-\(\frac{1}{10}\)
= \(\frac{5-3}{30}\)
\(\frac{1}{A}\)= \(\frac{2}{30}\)
A= 15 hours
Answer: C.
Kudos please if you like my explanation!
Work done by all of them in 1 hour is given by following equation:
\(\frac{1}{10}\)+\(\frac{1}{A}\)= \(\frac{1}{6}\)
\(\frac{1}{A}\)= \(\frac{1}{6}\)-\(\frac{1}{10}\)
= \(\frac{5-3}{30}\)
\(\frac{1}{A}\)= \(\frac{2}{30}\)
A= 15 hours
Answer: C.
Kudos please if you like my explanation!
15 May 2017, 02:17
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SajjadAhmad
Working together, Jeff and Ashley painted their apartment in 6 hours. If Jeff had been working alone, he could have painted the whole apartment in 10 hours. How many hours would it have taken Ashley to paint the apartment alone?
A. 4
B. 12
C. 15
D. 16
E. 20
A. 4
B. 12
C. 15
D. 16
E. 20
Jeff alone = 10 Hours (6 hours + 4 hours)
Jeff and Ashley together = 6 Hours
i.e. 6 Hours work of ashley replaces 4 hours work Jeff
i.e. 6 Hours work of Ashley = 4 hours work of Jeff
i.e. 3 Hours work of Ashley = 2 hours work of Jeff
i.e. Jeff = 1.5*Ashley
i.e. (1.5A + A) take 6 hours to finish work
i.e. 2.5 A takes 6 hours to finish work
i.e. A takes 6*2.5 = 15 hours to finish the work alone
Answer: Option C
