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(x^2 + 2x - 8)/(x^2 - 6x + 8) = ?

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(x^2 + 2x - 8)/(x^2 - 6x + 8) = ?  [#permalink]

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New post 28 Apr 2019, 16:40
3
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

80% (01:18) correct 20% (01:50) wrong based on 30 sessions

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\(\frac{x^2 + 2x - 8}{x^2 - 6x + 8}=?\)

A. 1

B. -1

C. \(\frac{1}{3}x\)

D. \(\frac{x+4}{x-4}\)

E. \(\frac{x+8}{x-8}\)

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Re: (x^2 + 2x - 8)/(x^2 - 6x + 8) = ?  [#permalink]

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New post 28 Apr 2019, 17:16
Numerator can be reduced as :

x^2+2x-8

x^2+4x-2x-8
(x-2)(x+4)

Denominator can be reduced as:

x^2-6x+8

x^2-4x-2x+8
(x-2)(x-4)

so the question is reduced in the form of

(x-2)(x+4)/(x-4)(x-2)

cancelling out give answer = -1
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Re: (x^2 + 2x - 8)/(x^2 - 6x + 8) = ?  [#permalink]

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New post 29 Apr 2019, 00:43
X^2+2x-8/x^2-6x+8
=x^2+4x-2x-8/x^2-4x+2x+8
=x(x+4)-2(x+4)/x(x-4)-2(x-4)
=(x-2)(x+4)/(x-2)(x-4)
=(x+4)/(x-4)
Option D

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Re: (x^2 + 2x - 8)/(x^2 - 6x + 8) = ?   [#permalink] 29 Apr 2019, 00:43
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