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# x^2=>x???

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Intern
Joined: 13 Jun 2010
Posts: 18

Kudos [?]: 29 [0], given: 0

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24 May 2013, 15:15
x^2 > x
=> x^2-x>0
=> x(x-1)>0
so x>0 or x>1.

Just curious x<0 also is valid for the above equation but when I solve mathematically I don't seem to get this as an option
Can you plase let me know where I am going wrong.

Thanks
gmatrant

Kudos [?]: 29 [0], given: 0

Joined: 29 Mar 2012
Posts: 323

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Location: India
GMAT 1: 640 Q50 V26
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GMAT 3: 730 Q50 V38

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24 May 2013, 22:39
gmatrant wrote:
x^2 > x
=> x^2-x>0
=> x(x-1)>0
so x>0 or x>1.

Just curious x<0 also is valid for the above equation but when I solve mathematically I don't seem to get this as an option
Can you plase let me know where I am going wrong.

Thanks
gmatrant

Hi,

x(x-1)>0 means, x<0 or x>1
for 0<x<1, x(x-1) < 0
Please check the post Solving Inequalities

Regards,

Kudos [?]: 499 [0], given: 23

Math Expert
Joined: 02 Sep 2009
Posts: 41698

Kudos [?]: 124613 [0], given: 12079

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25 May 2013, 03:19
gmatrant wrote:
x^2 > x
=> x^2-x>0
=> x(x-1)>0
so x>0 or x>1.

Just curious x<0 also is valid for the above equation but when I solve mathematically I don't seem to get this as an option
Can you plase let me know where I am going wrong.

Thanks
gmatrant

x^2>x --> x(x-1)>0. Both multiple must have the same sign:

x>0 and x-1>0 (x>1), so x>1.
x<0 and x-1<0 (x<1), so x<0.

Thus x^2>x holds true for x<0 and x>1.

Solving inequalities:
x2-4x-94661.html#p731476
inequalities-trick-91482.html
everything-is-less-than-zero-108884.html?hilit=extreme#p868863

Hope it helps.
_________________

Kudos [?]: 124613 [0], given: 12079

Re: x^2=>x???   [#permalink] 25 May 2013, 03:19
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