GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 18 Jun 2019, 08:06

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

 
e-GMAT Representative
User avatar
D
Joined: 04 Jan 2015
Posts: 2888
|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 26 May 2017, 05:21
1
16
00:00
A
B
C
D
E

Difficulty:

  95% (hard)

Question Stats:

36% (02:42) correct 64% (02:26) wrong based on 292 sessions

HideShow timer Statistics

|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and |y| < 5, what is the maximum possible value of -|xy|?


Answer Choices



    A. -12
    B. -6
    C. -4
    D. -2
    E. 0

Thanks,
Saquib
Quant Expert
e-GMAT

Register for our Free Session on Number Properties (held every 3rd week) to solve exciting 700+ Level Questions in a classroom environment under the real-time guidance of our Experts :)

Image

_________________
e-GMAT Representative
User avatar
D
Joined: 04 Jan 2015
Posts: 2888
Re: |x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 26 May 2017, 05:43
Intern
Intern
User avatar
B
Status: GMAT tutor
Joined: 20 Apr 2017
Posts: 20
GMAT 1: 770 Q49 V47
Re: |x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 26 May 2017, 05:46
2
EgmatQuantExpert wrote:
Q.

|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and |y| < 5, what is the maximum possible value of -|xy|?


Answer Choices



    A.-12
    B. -6
    C. -4
    D. -2
    E. 0

Thanks,
Saquib
Quant Expert
e-GMAT

Register for our Free Session on Number Properties (held every 3rd week) to solve exciting 700+ Level Questions in a classroom environment under the real-time guidance of our Experts :)

Image

Well, I don't 100% understand the question, but I'll take a stab at it.

Since y<5, 1 is a possible value for y. Since |1-4|=3, x would have to be 0 or 6 and that's not possible.

So I'm going to try -1, which yields |-1-4|=5 so x could be 2. That will yield answer choice (D), and I don't see how you can reach zero since neither x nor y can be zero. I'm going with D.
_________________
Elias Latour
Verbal Specialist @ ApexGMAT
blog.apexgmat.com
+1 (646) 736-7622
e-GMAT Representative
User avatar
D
Joined: 04 Jan 2015
Posts: 2888
Re: |x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 26 May 2017, 05:58
eliaslatour wrote:
Well, I don't 100% understand the question, but I'll take a stab at it.

Since y<5, 1 is a possible value for y. Since |1-4|=3, x would have to be 0 or 6 and that's not possible.

So I'm going to try -1, which yields |-1-4|=5 so x could be 2. That will yield answer choice (D), and I don't see how you can reach zero since neither x nor y can be zero. I'm going with D.



Nice try eliaslatour.

Though I won't comment whether is correct or not, as I want the others to also give it a shot. I just wanted to point out one error in your analysis.

When we write |y| < 5 and we remove the modulus from y, the range of y is not y < 5, but -5 < y < 5.

Apart from that, kudos to your observation that since x and y are non-zero integers, the value of -|xy| can never be 0. :)


Thanks,
Saquib
Quant Expert
e-GMAT

Register for our Free Session on Number Properties (held every 3rd week) to solve exciting 700+ Level Questions in a classroom environment under the real-time guidance of our Experts :)

Image
_________________
Current Student
User avatar
P
Joined: 18 Aug 2016
Posts: 617
Concentration: Strategy, Technology
GMAT 1: 630 Q47 V29
GMAT 2: 740 Q51 V38
GMAT ToolKit User Reviews Badge
Re: |x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 26 May 2017, 06:25
1
EgmatQuantExpert wrote:
Q.

|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and |y| < 5, what is the maximum possible value of -|xy|?


Answer Choices



    A.-12
    B. -6
    C. -4
    D. -2
    E. 0

Thanks,
Saquib
Quant Expert
e-GMAT

Register for our Free Session on Number Properties (held every 3rd week) to solve exciting 700+ Level Questions in a classroom environment under the real-time guidance of our Experts :)

Image




|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and |y| < 5, what is the maximum possible value of -|xy|

-5<x<5, -5<y<5

We need to solve for values of x & y to keep XY to minimum using |x + 3| = |y -4|

by value substitution x =2 and y=-1 fits the criteria keeping XY to minimum

hence option D
_________________
We must try to achieve the best within us


Thanks
Luckisnoexcuse
Manager
Manager
avatar
S
Joined: 03 Jan 2016
Posts: 57
Location: India
WE: Engineering (Energy and Utilities)
GMAT ToolKit User
Re: |x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 28 May 2017, 05:45
1
I tried as mentioned below

Given :

-5<x<5, -5<y<5 & x and y are non zero integers.

Therefore; x = {-4,-3,-2,-1,1,2,3,4} & y = {-4,-3,-2,-1,1,2,3,4}

|x + 3| = |y -4|

Try plugging above values
&
above equation holds when
1. x=-4 & y = 3
2. x=-3 & y= 4
3. x=2 & y =-1
4. x = 3 & y=-2
5. x=4 & y = -3.

- |xy| will be max when x=2 & y = -1

Option D

This is how i arrived.

Thanx
Narayana raju
Retired Moderator
User avatar
P
Joined: 19 Mar 2014
Posts: 929
Location: India
Concentration: Finance, Entrepreneurship
GPA: 3.5
GMAT ToolKit User
Re: |x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 19 Jun 2017, 16:08
1
1
This is a good and tricky question.

Given: lx+3l = ly-4l - x & y are non-zero integers.

lxl < 5
lyl < 5

Max of -lxyl = ?

As we have to find the max value, and the final max number will be negative as -lxyl will be negative, we need to ensure that we get smallest value of negative possible which satisfies given equation.

As per given information values of x and y can range as per below:

-5 < x < 5
-5 < y < 5

As we have to take least numbers, we will plug numbers from this range.

Note we cannot take x & y as zero as per the given information, also it does not satisfy the given equation lx+3l = ly-4l.

Only values we can check for us -1 & 2 or 2 & -1

so maximum value we get is -2.

Hence, Answer is D = -2
_________________
"Nothing in this world can take the place of persistence. Talent will not: nothing is more common than unsuccessful men with talent. Genius will not; unrewarded genius is almost a proverb. Education will not: the world is full of educated derelicts. Persistence and determination alone are omnipotent."

Best AWA Template: https://gmatclub.com/forum/how-to-get-6-0-awa-my-guide-64327.html#p470475
Senior Manager
Senior Manager
avatar
P
Joined: 18 Feb 2019
Posts: 451
Location: India
GMAT 1: 460 Q42 V13
GPA: 3.6
|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 29 Mar 2019, 12:40
1
|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and |y| < 5, what is the maximum possible value of -|xy|?

A. -12
B. -6
C. -4
D. -2
E. 0
Math Expert
User avatar
V
Joined: 02 Aug 2009
Posts: 7757
|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 29 Mar 2019, 16:54
1
kiran120680 wrote:
|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and |y| < 5, what is the maximum possible value of -|xy|?

A. -12
B. -6
C. -4
D. -2
E. 0


To maximize -|xy|, we have to minimize |xy|

Possible cases |x + 3| = |y -4|
(I) \(x+3=y-4....x=y-7\)........|xy|=|y(y-7)|... |y(y-7)| will be at least 6 even if we take y as 1.
(II) \(-(x+3)=y-4....-x-3=y-4................y+x=1\).....let us take minimum possible value for this. Both are non-zero, so one of them 2 and other -1 will fit and |xy|=|2(-1)|=|2|

so maximum value of -|xy|=-|2|. No need to check further as in the options the max value is -2.
0 cannot be a value as both x and y are non-zero.

D
_________________
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 55668
Re: |x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 30 Mar 2019, 00:29
CEO
CEO
User avatar
P
Joined: 18 Aug 2017
Posts: 3879
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
GMAT ToolKit User Premium Member CAT Tests
Re: |x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 30 Mar 2019, 01:00
kiran120680 wrote:
|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and |y| < 5, what is the maximum possible value of -|xy|?

A. -12
B. -6
C. -4
D. -2
E. 0


simplify the expression
|x + 3| = |y -4|
x+3= y-4
x-y=-7
or say
-x-3=y-4
-(x+y)=-1
x+y=1
so x=2 and y=-1
possible and it satisfies
|x + 3| = |y -4|
-lxyl ; -2
IMO D
_________________
If you liked my solution then please give Kudos. Kudos encourage active discussions.
Senior Manager
Senior Manager
avatar
P
Joined: 09 Jun 2014
Posts: 269
Location: India
Concentration: General Management, Operations
Schools: Tuck '19
Premium Member Reviews Badge CAT Tests
Re: |x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 27 Apr 2019, 03:13
Archit3110 wrote:
kiran120680 wrote:
|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and |y| < 5, what is the maximum possible value of -|xy|?

A. -12
B. -6
C. -4
D. -2
E. 0


simplify the expression
|x + 3| = |y -4|
x+3= y-4
x-y=-7
or say
-x-3=y-4
-(x+y)=-1
x+y=1
so x=2 and y=-1
possible and it satisfies
|x + 3| = |y -4|
-lxyl ; -2
IMO D



correct me if am wrong but the solution of eqution in red is x=-3 and y=4

I tried a simlar approach and was struck for quite a bit .

Press kudos if it helps!!
Senior Manager
Senior Manager
avatar
P
Joined: 09 Jun 2014
Posts: 269
Location: India
Concentration: General Management, Operations
Schools: Tuck '19
Premium Member Reviews Badge CAT Tests
Re: |x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 27 Apr 2019, 03:19
chetan2u wrote:
kiran120680 wrote:
|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and |y| < 5, what is the maximum possible value of -|xy|?

A. -12
B. -6
C. -4
D. -2
E. 0


To maximize -|xy|, we have to minimize |xy|

Possible cases |x + 3| = |y -4|
(I) \(x+3=y-4....x=y-7\)........|xy|=|y(y-7)|... |y(y-7)| will be at least 6 even if we take y as 1.
(II) \(-(x+3)=y-4....-x-3=y-4................y+x=1\).....let us take minimum possible value for this. Both are non-zero, so one of them 2 and other -1 will fit and |xy|=|2(-1)|=|2|

so maximum value of -|xy|=-|2|. No need to check further as in the options the max value is -2.
0 cannot be a value as both x and y are non-zero.

D



hello Egmat/Chetan sir,

I tried solving the inequalities and landed up withe x=-3 and y=4.

Can you please suggest the right line of thinking when seeing such questions..I see your approach is clear...But seeing inequalities like this general tendency is to jump into solving them.
Here after seeing the options it didnt help rather just plugging in values from options(assuming |x|<4 and |y|<5 wold have been far more beneficial)
Intern
Intern
avatar
Joined: 03 Jun 2014
Posts: 4
Location: Viet Nam
GPA: 3.3
WE: Research (Consulting)
|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and  [#permalink]

Show Tags

New post 27 Apr 2019, 05:29
1
1
I think this type of question is not too difficult if we solve things step by step. Below is my approach:

First things first, we have |x| < 5 and |y| < 5, which mean -5 < x < 5 and -5 < y < 5

Then, solve the equation:|x + 3| = |y -4|

We apply this: |A| = |B| then A = B or A = -B

=> x+3 = y-4 or x+3 = 4-y
=> x - y = -7 or x + y = 1

The possible values of x and y may be:
1. x - y = -7 -> pairs of value (x,y) can be: (-4;3) or (-3;4)
2. x + y = 1 -> (-1;2) or (-2;3) or (-3;4)

Then -|xy| can get these following values: -2, -6, -12 => -2 is the highest => D
GMAT Club Bot
|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and   [#permalink] 27 Apr 2019, 05:29
Display posts from previous: Sort by

|x + 3| = |y -4|, where x and y are non-zero integers. If |x| < 5 and

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne