aviejay wrote:
Bunuel wrote:
X and Y are both integers. If X/Y = 59.32, then what is the sum of all the possible two digit remainders of X/Y?
A. 560
B. 616
C. 672
D. 900
E. 1024
Hi
Bunuel,
Could you please explain the concept needed to solve this problem? This would be of great help.
Thanks.
Well I am not him but just went through that problem.
There is a rule that you can apply with decimals and remainder question that the digits behind the decimal (in this case 0.32) equivalent "Remainder / Divisor"
In this case this would mean "32/100"
The tricky thing about this rule is that you can't determine with a hundert percent certainty what the actual combination of remainder and divisor is.
Think about it -> 8 / 25 = 0.32 as well which would be the same as a remainder of 32 and a divisor of 100.
In this question they only ask about the sum of the two digit remainders so we go from 8 / 25 up to all the way to 100 in steps of 8.
which means 16 , 24 , 32 .... 96
\((96+16)/2 =56\)
\((56*11)=616\)
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