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x and y are nonnegative integers. If xy+2x+3y=0, then y=?
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25 Oct 2018, 23:55
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[ Math Revolution GMAT math practice question] \(x\) and \(y\) are nonnegative integers. If \(xy+2x+3y=0\), then \(y=?\) \(A. 0\) \(B. 1\) \(C. 2\) \(D. 3\) \(E. 4\)
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Re: x and y are nonnegative integers. If xy+2x+3y=0, then y=?
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26 Oct 2018, 00:02
MathRevolution wrote: [ Math Revolution GMAT math practice question] \(x\) and \(y\) are nonnegative integers. If \(xy+2x+3y=0\), then \(y=?\) \(A. 0\) \(B. 1\) \(C. 2\) \(D. 3\) \(E. 4\) \(xy+2x+3y=0\) i.e. \(xy+2x+3y+66 =0\) i.e. \(x(y+2)+3(y+2)6 =0\) i.e. \((y+2)*(x+3) =6\) But 2*3 = 6 i.e. y = 0 and x = 0 is the only possible case we get because x and y are NONNEGATIVE integers Answer: Option A
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Re: x and y are nonnegative integers. If xy+2x+3y=0, then y=?
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26 Oct 2018, 02:02
xy+2x+3y=0 is possible only when both x and y are equal to 0. So Answer must be A.
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Re: x and y are nonnegative integers. If xy+2x+3y=0, then y=?
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26 Oct 2018, 02:27
By carefully observing the equation, we can say that for all values of \(y\geq1\) the RHS part fo the equation will be a negative value. So the only value that satisfies the equation is \(Zero\). OPTION : A
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x and y are nonnegative integers. If xy+2x+3y=0, then y=?
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26 Oct 2018, 04:13
MathRevolution wrote: [ Math Revolution GMAT math practice question] \(x\) and \(y\) are nonnegative integers. If \(xy+2x+3y=0\), then \(y=?\) \(A. 0\) \(B. 1\) \(C. 2\) \(D. 3\) \(E. 4\) whenever the the phrase " nonnegative" is used , pay special attention to Zero. It's test makers silent trick.
xy + 2x + 3y = 0
How?
If x = 0
xy = 0
2x = 0
but still we have 3y.
2 variables in this question.
say y = 0
xy = 0
3y = 0
but what's about 2x.
So, both x and y are 0 as ultimate result is 0.
Number plugging is helpful here. Back solving is also useful. But remember that ultimate result is 0 and u have 2 variables.
The best answer is A.



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Re: x and y are nonnegative integers. If xy+2x+3y=0, then y=?
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26 Oct 2018, 04:48
MathRevolution wrote: [ Math Revolution GMAT math practice question] \(x\) and \(y\) are nonnegative integers. If \(xy+2x+3y=0\), then \(y=?\) \(A. 0\) \(B. 1\) \(C. 2\) \(D. 3\) \(E. 4\) NONNEGATIVE implies that we should test ZERO. Let x=0. Substituting x=0 into xy + 2x + 3y = 0, we get: 0*y + 2*0 + 3y = 0 3y = 0 y = 0
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Re: x and y are nonnegative integers. If xy+2x+3y=0, then y=?
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26 Oct 2018, 22:57
xx and yy are nonnegative integers. If xy+2x+3y=0xy+2x+3y=0, then y=?y=? A.0A.0 B.1B.1 C.2C.2 D.3D.3 E.4 Plug in for values of y only at y=0 we get is a even +ve integer value which is x=0
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Re: x and y are nonnegative integers. If xy+2x+3y=0, then y=?
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28 Oct 2018, 18:19
=> \(xy+2x+3y=0\) \(=> xy+2x+3y+6=6\) \(=> (x+3)(y+2)=6\) Since \(x\) and \(y\) are integers, \(x+3\) and \(y+2\) are integers. The possible pairs \((x+3,y+2)\) are as follows: \(( x+3, y+2 ) = (1,6), (2,3), (3,2), (6,1), (1,6), (2,3), (3,2)\) and \((6,1).\) The corresponding pairs \((x,y)\) are: \((x,y) = (2,4), (1,2), (0,0), (3,1), (4,8), (5,5), (6,4)\) and \((9,3).\) The unique pair with nonnegative \(x\) and \(y\) is \((x,y)=(0,0).\) Thus, \(y = 0.\) Therefore, the answer is A. Answer: A
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Re: x and y are nonnegative integers. If xy+2x+3y=0, then y=?
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08 Nov 2018, 18:38
y(x+3) + 2x=0 y=2x/(x+3)
only way y can be nonnegative is if y=0




Re: x and y are nonnegative integers. If xy+2x+3y=0, then y=? &nbs
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08 Nov 2018, 18:38






