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Re: X intercept of the line L is negative. If the slope of the line [#permalink]
gmatbusters wrote:
Good approach david,

Another approach.

Equation of line is: y = mx +c
Slope, m is positive
x-intercept is negative, hence -c/m <0
hence c is negative, or y-intercept is negative.
Answer is C


think you have a typo there :)
-c/m <0 --> -c<0 --> c>0
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Re: X intercept of the line L is negative. If the slope of the line [#permalink]
Expert Reply
Oops, thanks for pointing out, I will revise it.


DavidTutorexamPAL wrote:
gmatbusters wrote:
Good approach david,

Another approach.

Equation of line is: y = mx +c
Slope, m is positive
x-intercept is negative, hence -c/m <0
hence c is negative, or y-intercept is negative.
Answer is C


think you have a typo there :)
-c/m <0 --> -c<0 --> c>0
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X intercept of the line L is negative. If the slope of the line [#permalink]
pushpitkc wrote:
X intercept of the line L is negative. If the slope of the line is positive, which of
the following could be a possible value of the Y-intercept of L?

I 0
II 1
III -2

A. I only
B. II only
C. III only
D. II and III only
E. I, II, and III

Source: Experts Global




1st Point : (-x,0) 2nd Point: (0,y)

Slope = (y2-y1)/(x2-x1)
Here we get,

(y-0)/(0-(-x)) >> y/x

The slope is positive as per question, so we need positive value for 'y' in the numerator.
Hence, Option C is the answer.
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Re: X intercept of the line L is negative. If the slope of the line [#permalink]
riagarg07

The slope is positive as per question, so we need positive value for 'y' in the numerator. That is why answer is B and not C. :)
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Re: X intercept of the line L is negative. If the slope of the line [#permalink]
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