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# x/|x| < x. Which must be true? x > 1 x> -1 |x| <

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CEO
Joined: 21 Jan 2007
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x/|x| < x. Which must be true? x > 1 x> -1 |x| < [#permalink]

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17 Dec 2007, 09:15
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

x/|x| < x. Which must be true?

x > 1
x> -1
|x| < 1
|X| = 1
|x|^2 > 1
Manager
Joined: 20 Jun 2007
Posts: 156
Followers: 1

Kudos [?]: 19 [0], given: 0

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17 Dec 2007, 09:22
Can't think of a clever way to do this, but it's quick to try a few numbers:

1/2 : 1 < 1/2 not true
1: 1 < 1 not true
2: 1 < 2 true
-1: -1 < -1 not true
-2 -1 <2>-1, B.
SVP
Joined: 29 Aug 2007
Posts: 2476
Followers: 69

Kudos [?]: 774 [0], given: 19

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17 Dec 2007, 10:23
bmwhype2 wrote:
x/|x| < x. Which must be true?

x > 1
x> -1
|x| < 1
|X| = 1
|x|^2 > 1

A. x / |x| < x only when x>1 because x/lxl can be either -1, 1, or infinitive but infinitive doesnot solve the problem. so only if x >1, x > x/lxl. if x >-1, x is not greater than x/lxl if x is a +ve fraction.

therefore, x > 1. So A.
SVP
Joined: 01 May 2006
Posts: 1796
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Kudos [?]: 154 [0], given: 0

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17 Dec 2007, 10:42
Here, other explanations : http://www.gmatclub.com/forum/t54918
CEO
Joined: 21 Jan 2007
Posts: 2747
Location: New York City
Followers: 11

Kudos [?]: 938 [0], given: 4

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17 Dec 2007, 10:57
how do i search for "X / |X| < x"
SVP
Joined: 01 May 2006
Posts: 1796
Followers: 9

Kudos [?]: 154 [0], given: 0

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17 Dec 2007, 12:34
bmwhype2 wrote:
how do i search for "X / |X| < x"

Indeed, it's not possible
17 Dec 2007, 12:34
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