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# x, y, a, and b are positive integers. When x is divided by

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Intern
Joined: 02 Mar 2007
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x, y, a, and b are positive integers. When x is divided by [#permalink]

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23 Mar 2008, 21:22
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

x, y, a, and b are positive integers. When x is divided by y, the remainder is 6. When a is divided by b, the remainder is 9. Which of the following is NOT a possible value for y + b?

a. 24
b. 21
c. 20
d. 17
e. 15

found this problem on Manhattan GMAT. besides answering this question. does anyone any equations for formulas to tackle remainder questions? Are these type of questions always conceptual?

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Senior Manager
Joined: 15 Aug 2007
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23 Mar 2008, 21:51
E

To get those remainders, y and b should be greaterthan 9 and 6, so adding them up - 15.

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Intern
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24 Mar 2008, 16:23
I found the solution but thanks for the explanation. I have a more detail explanation for those who are interested.

The problem states that when x is divided by y the remainder is 6. In general, the divisor (y in this case) will always be greater than the remainder. To illustrate this concept, let's look at a few examples:

15/4 gives 3 remainder 3 (the divisor 4 is greater than the remainder 3)
25/3 gives 8 remainder 1 (the divisor 3 is greater than the remainder 1)
46/7 gives 6 remainder 4 (the divisor 7 is greater than the remainder 4)

In the case at hand, we can therefore conclude that y must be greater than 6.

The problem also states that when a is divided by b the remainder is 9. Therefore, we can conclude that b must be greater than 9.

If y > 6 and b > 9, then y + b > 6 + 9 > 15. Thus, 15 cannot be the sum of y and b.

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Director
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24 Mar 2008, 18:17
This problem is about the common sense rather than the concepts.

divisor can't be equal to the remainder.
that's why y is not equal to 6
Same way, b is not equal to 9
hence y+b can't be equal to 15

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Re: challenging remainder problem!   [#permalink] 24 Mar 2008, 18:17
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