It is currently 28 Jun 2017, 04:07

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# x<y and z>0 which of the following must be true?

Author Message
Manager
Joined: 25 Feb 2008
Posts: 53
x<y and z>0 which of the following must be true? [#permalink]

### Show Tags

20 Mar 2008, 07:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

x<y and z>0 which of the following must be true?

z/x<z/y
y/z<x/z
x>y/z
z-x<z-y
xz<yz
Manager
Joined: 20 Aug 2007
Posts: 65

### Show Tags

20 Mar 2008, 07:36
Capthan wrote:
x<y and z>0 which of the following must be true?

z/x<z/y
y/z<x/z
x>y/z
z-x<z-y
xz<yz

just plug in number and u'll get the answer
Director
Joined: 10 Sep 2007
Posts: 938

### Show Tags

20 Mar 2008, 07:41
Please remember that z is +ve as given in the question.

A: z/x<z/y Dividing by z both side we have => 1/x < 1/y.
We are not told about x and y being +ve or -ve only thing is that x<y. So this one might or might not hold.

B: y/z<x/z, Multiplyig both sides by z, we have y<x. Not true as given in question x<y.

C: x>y/z, Multiplyig both sides by z, we have y<zx. Since we do not have fixed values for x,y, and z so there is infinite possibilities to satisfy or not satisfy this inequality.

D: z-x<z-y. Substracting z from both side, we have -x<-y => y<x. Not true as given in question x<y.

E: xz<yz Dividing by z both side we have => x<y, which is given in the question.

Re: x<y   [#permalink] 20 Mar 2008, 07:41
Display posts from previous: Sort by