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# X/Y has a unknown remainder. Both X and Y are positive

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CEO
Joined: 21 Jan 2007
Posts: 2747
Location: New York City
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X/Y has a unknown remainder. Both X and Y are positive [#permalink]

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25 Oct 2007, 06:54
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

X/Y has a unknown remainder.
Both X and Y are positive integers.
X/Y = 2.625

The unknown remainder can be 5 because it is divisible by .625.

My question: Why is the unknown remainder 5 divided by .625?
VP
Joined: 10 Jun 2007
Posts: 1443
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25 Oct 2007, 07:11
bmwhype2 wrote:
X/Y has a unknown remainder.
Both X and Y are positive integers.
X/Y = 2.625

The unknown remainder can be 5 because it is divisible by .625.

My question: Why is the unknown remainder 5 divided by .625?

2.625 = 2 + 625/1000 = 2 + 5/8
Senior Manager
Joined: 27 Aug 2007
Posts: 253
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25 Oct 2007, 07:14
I didn't understand your question, But if you write 0.625 as 625/1000=5/8 than it is clearly seen that 5 is remainder.

I hope this was something you were looking for...
25 Oct 2007, 07:14
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