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Xavier and Adam are riding motorcycles down the highway at constant sp

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Manager
Joined: 02 Jun 2015
Posts: 190
Location: Ghana
Xavier and Adam are riding motorcycles down the highway at constant sp  [#permalink]

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27 Feb 2017, 07:39
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Difficulty:

45% (medium)

Question Stats:

66% (01:32) correct 34% (01:50) wrong based on 166 sessions

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Xavier and Adam are riding motorcycles down the highway at constant speeds. If Xavier is now 2 miles ahead of Adam, how many minutes before Xavier is 3 miles ahead of Adam?

(1) Xavier is traveling 12 miles per hour faster than Adam.
(2) In 8 minutes, Xavier has increased the distance between himself and Adam by 1/2 mile.

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Intern
Joined: 18 Jan 2016
Posts: 3
Re: Xavier and Adam are riding motorcycles down the highway at constant sp  [#permalink]

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15 Mar 2017, 03:55
1
The question asks for the time by which the distance between X and A is 3 (or the distance between X and A is 1, if you consider as starting point the moment in which they are 2 miles apart).

Request: (Vx*t+2)-(Va*t)=3 - [or (Vx*t)-(Va*t)=1]

(1) Vx=12+Va --> 12*t+Va*t-Va*t=1 --> t=(1/12 hr)*(60mins/hr)=5mins SUFF

(2) Vx*8-Va*8=0,5 --> t=8*2=16 mins SUFF

Intern
Joined: 14 Nov 2012
Posts: 23
GMAT 1: 740 Q51 V38
Re: Xavier and Adam are riding motorcycles down the highway at constant sp  [#permalink]

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13 Sep 2017, 01:38
1
duahsolo wrote:
Xavier and Adam are riding motorcycles down the highway at constant speeds. If Xavier is now 2 miles ahead of Adam, how many minutes before Xavier is 3 miles ahead of Adam?

(1) Xavier is traveling 12 miles per hour faster than Adam.
(2) In 8 minutes, Xavier has increased the distance between himself and Adam by 1/2 mile.

1. For every hour, their gap increases by 12 miles.
=> for 3-2=1 mile gap, it would take 1/12 hour
Sufficient

2. The same deduction method as 1)
Suff

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Intern
Joined: 10 May 2017
Posts: 5
Re: Xavier and Adam are riding motorcycles down the highway at constant sp  [#permalink]

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22 Oct 2017, 01:14
carlopanieri wrote:
The question asks for the time by which the distance between X and A is 3 (or the distance between X and A is 1, if you consider as starting point the moment in which they are 2 miles apart).

Request: (Vx*t+2)-(Va*t)=3 - [or (Vx*t)-(Va*t)=1]

(1) Vx=12+Va --> 12*t+Va*t-Va*t=1 --> t=(1/12 hr)*(60mins/hr)=5mins SUFF

(2) Vx*8-Va*8=0,5 --> t=8*2=16 mins SUFF

How have you assumed that both Xavier and Adam have equal times(t1=t2=t)?
Shouldn't it be a different time period.
Bunuel
Would love your explanation for this entire problem
Re: Xavier and Adam are riding motorcycles down the highway at constant sp &nbs [#permalink] 22 Oct 2017, 01:14
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