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Xavier and Adam are riding motorcycles down the highway at constant sp

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Joined: 02 Jun 2015
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Xavier and Adam are riding motorcycles down the highway at constant sp [#permalink]

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New post 27 Feb 2017, 07:39
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Question Stats:

66% (01:15) correct 34% (01:16) wrong based on 132 sessions

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Xavier and Adam are riding motorcycles down the highway at constant speeds. If Xavier is now 2 miles ahead of Adam, how many minutes before Xavier is 3 miles ahead of Adam?

(1) Xavier is traveling 12 miles per hour faster than Adam.
(2) In 8 minutes, Xavier has increased the distance between himself and Adam by 1/2 mile.
[Reveal] Spoiler: OA

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Re: Xavier and Adam are riding motorcycles down the highway at constant sp [#permalink]

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New post 15 Mar 2017, 03:55
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The question asks for the time by which the distance between X and A is 3 (or the distance between X and A is 1, if you consider as starting point the moment in which they are 2 miles apart).

Request: (Vx*t+2)-(Va*t)=3 - [or (Vx*t)-(Va*t)=1]

(1) Vx=12+Va --> 12*t+Va*t-Va*t=1 --> t=(1/12 hr)*(60mins/hr)=5mins SUFF

(2) Vx*8-Va*8=0,5 --> t=8*2=16 mins SUFF

Hence, the answer is D.

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Re: Xavier and Adam are riding motorcycles down the highway at constant sp [#permalink]

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New post 13 Sep 2017, 01:38
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duahsolo wrote:
Xavier and Adam are riding motorcycles down the highway at constant speeds. If Xavier is now 2 miles ahead of Adam, how many minutes before Xavier is 3 miles ahead of Adam?

(1) Xavier is traveling 12 miles per hour faster than Adam.
(2) In 8 minutes, Xavier has increased the distance between himself and Adam by 1/2 mile.


1. For every hour, their gap increases by 12 miles.
=> for 3-2=1 mile gap, it would take 1/12 hour
Sufficient

2. The same deduction method as 1)
Suff

Posted from my mobile device

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Re: Xavier and Adam are riding motorcycles down the highway at constant sp [#permalink]

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New post 22 Oct 2017, 01:14
carlopanieri wrote:
The question asks for the time by which the distance between X and A is 3 (or the distance between X and A is 1, if you consider as starting point the moment in which they are 2 miles apart).

Request: (Vx*t+2)-(Va*t)=3 - [or (Vx*t)-(Va*t)=1]

(1) Vx=12+Va --> 12*t+Va*t-Va*t=1 --> t=(1/12 hr)*(60mins/hr)=5mins SUFF

(2) Vx*8-Va*8=0,5 --> t=8*2=16 mins SUFF

Hence, the answer is D.

How have you assumed that both Xavier and Adam have equal times(t1=t2=t)?
Shouldn't it be a different time period.
Bunuel
Would love your explanation for this entire problem

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Re: Xavier and Adam are riding motorcycles down the highway at constant sp   [#permalink] 22 Oct 2017, 01:14
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Xavier and Adam are riding motorcycles down the highway at constant sp

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