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# xy plane

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Manager
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02 Jan 2006, 18:26
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02 Jan 2006, 19:15
from i, m = -ve. the line can pass through (a, b) = (2, 1), (1, 2) (-2, -1), (-1, 2), (2, -1) and so on.
From ii, b>a. (a,b) could be any values for example (1, 2) (-2, -1)

E. i donot see it is C.

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02 Jan 2006, 20:00
I thought that a negative slope meant that the line had to run (for lack of a better term) from Northwest to Southeast - always down and to the right? Is that incorrect?

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02 Jan 2006, 20:59
HIMALAYA wrote:
from i, m = -ve. the line can pass through (a, b) = (2, 1), (1, 2) (-2, -1), (-1, 2), (2, -1) and so on.
From ii, b>a. (a,b) could be any values for example (1, 2) (-2, -1)

E. i donot see it is C.

C is correct. taking both statements we can determine that the any point on the line is either in fourth or 2nd quadrant. with statement 2 we can locate the point in fourth quad with -ve X and +ve Y

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02 Jan 2006, 21:08
old_dream_1976 wrote:
HIMALAYA wrote:
from i, m = -ve. the line can pass through (a, b) = (2, 1), (1, 2) (-2, -1), (-1, 2), (2, -1) and so on.
From ii, b>a. (a,b) could be any values for example (1, 2) (-2, -1)

E. i donot see it is C.

C is correct. taking both statements we can determine that the any point on the line is either in fourth or 2nd quadrant. with statement 2 we can locate the point in fourth quad with -ve X and +ve Y

oohhhhhhh thats correct.

the line passes through orgin to a,b.

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02 Jan 2006, 21:11
I will take E here.

From 1) Line k is of the form y = -mx+c (c being the y intercept; See attached picture)
From 2) a < b
=> b = -ma + c

Depending on the value of c, the line pass through different quandrant (See attached picture)
HTH.
Attachments

line.GIF [ 3.2 KiB | Viewed 742 times ]

_________________

"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."

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02 Jan 2006, 21:24
C it is.

the slope of the line = (b-0)/(a -0)= b/a
from 1, b/a < 0
from 2, we have a<b

Combine two statements, it must be that: a< 0 <b
--> b is positive --> suff

Last edited by laxieqv on 02 Jan 2006, 21:27, edited 2 times in total.

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02 Jan 2006, 21:25
giddi77

Remember the line passes thru the origin and therefore your figure is incorrect.

The correct answer is C. The point (a,b) is in the IInd quadrant, where the y-axis -point b- is positive.

spiderman_xx

giddi77 wrote:
I will take E here.

From 1) Line k is of the form y = -mx+c (c being the y intercept; See attached picture)
From 2) a < b
=> b = -ma + c

Depending on the value of c, the line pass through different quandrant (See attached picture)
HTH.

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02 Jan 2006, 21:29
laxieqv wrote:
C it is.

the slope of the line = (b-0)/(a -0)= b/a
from 1, b/a < 0
from 2, we have a<b

Combine two statements, it must be that: a<0<b --> b is positive --> suff

laxie you are right, I missed the passing through the origin part. Thanks for the explanation.
_________________

"To dream anything that you want to dream, that is the beauty of the human mind. To do anything that you want to do, that is the strength of the human will. To trust yourself, to test your limits, that is the courage to succeed."

- Bernard Edmonds

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02 Jan 2006, 21:34
giddi77 wrote:
laxieqv wrote:
C it is.

the slope of the line = (b-0)/(a -0)= b/a
from 1, b/a < 0
from 2, we have a<b

Combine two statements, it must be that: a<0<b --> b is positive --> suff

laxie you are right, I missed the passing through the origin part. Thanks for the explanation.

The forum has technical errors, I typed a < 0 < b and it turns " a<0 b "

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02 Jan 2006, 21:34
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