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(y^2/25 + y^2/16)^(1/2) =

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New post 04 Mar 2018, 23:11
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A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

71% (01:25) correct 29% (01:23) wrong based on 141 sessions

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New post 05 Mar 2018, 00:17
Bunuel wrote:
\(\sqrt{\frac{y^2}{25} + \frac{y^2}{16}} =\)


A. \(\frac{2|y|}{9}\)

B. \(\frac{9|y|}{20}\)

C. \(\frac{|y|}{9}\)

D. \(\frac{|y|*\sqrt{41}}{20}\)

E. \(\frac{41|y|}{20}\)


\(\sqrt{\frac{y^2}{25} + \frac{y^2}{16}}\) = \(\sqrt{\frac{25*y^2 + 16*y^2}{25*16}}\) = \(\sqrt{\frac{41*y^2}{400}} = \frac{\sqrt{41*y^2}}{\sqrt400}\) = \({\frac{\sqrt41*|y|}{20}}\) (Option D)
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New post 25 Mar 2018, 05:54

Solution



=\(\sqrt{(\frac{y^2}{25}+ \frac{y^2}{16})}\)

= \(\sqrt{\frac{(16 y^2+25y^2)}{(25*16)}}\)

= \(\sqrt{\frac{41 y^2}{400}}\)

= \(\sqrt{\frac{41(y)^2}{(20)^2}}\)

\(\sqrt{\frac{y^2}{25}+ \frac{y^2}{16}} = |y| *\sqrt{\frac{41}{20}}\)

Answer: D
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Re: (y^2/25 + y^2/16)^(1/2) =  [#permalink]

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New post 25 Mar 2018, 06:37
Bunuel wrote:
\(\sqrt{\frac{y^2}{25} + \frac{y^2}{16}} =\)


A. \(\frac{2|y|}{9}\)

B. \(\frac{9|y|}{20}\)

C. \(\frac{|y|}{9}\)

D. \(\frac{|y|*\sqrt{41}}{20}\)

E. \(\frac{41|y|}{20}\)



\(\sqrt{\frac{y^2}{25} + \frac{y^2}{16}}\)
= \(|y|\sqrt{\frac{1}{25} + \frac{1}{16}}\)
= \(|y|\sqrt{\frac{(16+25)}{25*16}}\)
= \(\frac{|y|}{20}\sqrt{(16+25)}\)
= \(\frac{|y|}{20}\sqrt{41}\) Ans B
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Re: (y^2/25 + y^2/16)^(1/2) =   [#permalink] 25 Mar 2018, 06:37
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