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Yesterday Diana spent a total of 240 minutes attending a

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Intern
Joined: 22 Jun 2010
Posts: 42
Yesterday Diana spent a total of 240 minutes attending a [#permalink]

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07 Sep 2010, 15:37
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Yesterday Diana spent a total of 240 minutes attending a training class, responding to E-mails, and talking on the phone. If she did no two of these three activities at the same time, how much time did she spend talking on the phone?

(1) Yesterday the amount of time that Diana spent attending the training class was 90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was 60 percent of the total amount of time that she spent responding to E-mails and talking on the phone.
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07 Sep 2010, 15:48
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mehdiov wrote:
Yesterday Diana spent a total of 240 minutes attending a training class, responding to E-
mails, and talking on the phone. If she did no two of these three activities at the same
time, how much time did she spend talking on the phone?
(1) Yesterday the amount of time that Diana spent attending the training class was
90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was
60 percent of the total amount of time that she spent responding to E-mails and
talking on the phone.

Given: $$C+E+P=240$$, where C is th time she spent on training class, E is the time she spent on E-mail and P is the time she spent on phone. Question: $$P=?$$

(1) $$C=0.9E$$ --> $$C+E+P=0.9E+E+P=1.9E+P=240$$. Not sufficient to calculate $$P$$ (one equation, two variables).

(2) $$C=0.6(E+P)$$ --> $$C+E+P=0.6(E+P)+E+P=1.6E+1.6P=240$$. Not sufficient to calculate $$P$$ (one equation, two variables).

(1)+(2) $$1.9E+P=240$$ and $$1.6E+1.6P=240$$ --> we have two distinct linear equations with two variables hence we can calculate each of them. Sufficient.

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22 Oct 2013, 07:02
Bunuel wrote:
mehdiov wrote:
Yesterday Diana spent a total of 240 minutes attending a training class, responding to E-
mails, and talking on the phone. If she did no two of these three activities at the same
time, how much time did she spend talking on the phone?
(1) Yesterday the amount of time that Diana spent attending the training class was
90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was
60 percent of the total amount of time that she spent responding to E-mails and
talking on the phone.

Given: $$C+E+P=240$$, where C is th time she spent on training class, E is the time she spent on E-mail and P is the time she spent on phone. Question: $$P=?$$

(1) $$C=0.9E$$ --> $$C+E+P=0.9E+E+P=1.9E+P=240$$. Not sufficient to calculate $$P$$ (one equation, two variables).

(2) $$C=0.6(E+P)$$ --> $$C+E+P=0.6(E+P)+E+P=1.6E+1.6P=240$$. Not sufficient to calculate $$P$$ (one equation, two variables).

(1)+(2) $$1.9E+P=240$$ and $$1.6E+1.6P=240$$ --> we have two distinct linear equations with two variables hence we can calculate each of them. Sufficient.

Bunuel, for statement 2 we can rearrange to get E+P=240/1.6. If we have E+P, cant we plug this into C+E+P=240, which gives us C+(240/1.6)=240, which gives us C=240-(240/1.6)? Hence 2 would be sufficient as you rearrange to get P?
Math Expert
Joined: 02 Sep 2009
Posts: 39704

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22 Oct 2013, 07:56
bulletpoint wrote:
Bunuel wrote:
mehdiov wrote:
Yesterday Diana spent a total of 240 minutes attending a training class, responding to E-
mails, and talking on the phone. If she did no two of these three activities at the same
time, how much time did she spend talking on the phone?
(1) Yesterday the amount of time that Diana spent attending the training class was
90 percent of the amount of time that she spent responding to E-mails.
(2) Yesterday the amount of time that Diana spent attending the training class was
60 percent of the total amount of time that she spent responding to E-mails and
talking on the phone.

Given: $$C+E+P=240$$, where C is th time she spent on training class, E is the time she spent on E-mail and P is the time she spent on phone. Question: $$P=?$$

(1) $$C=0.9E$$ --> $$C+E+P=0.9E+E+P=1.9E+P=240$$. Not sufficient to calculate $$P$$ (one equation, two variables).

(2) $$C=0.6(E+P)$$ --> $$C+E+P=0.6(E+P)+E+P=1.6E+1.6P=240$$. Not sufficient to calculate $$P$$ (one equation, two variables).

(1)+(2) $$1.9E+P=240$$ and $$1.6E+1.6P=240$$ --> we have two distinct linear equations with two variables hence we can calculate each of them. Sufficient.

Bunuel, for statement 2 we can rearrange to get E+P=240/1.6. If we have E+P, cant we plug this into C+E+P=240, which gives us C+(240/1.6)=240, which gives us C=240-(240/1.6)? Hence 2 would be sufficient as you rearrange to get P?

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Re: Yesterday Diana spent a total of 240 minutes attending a [#permalink]

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04 Dec 2014, 23:51
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: Yesterday Diana spent a total of 240 minutes attending a [#permalink]

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10 Sep 2016, 13:46
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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Re: Yesterday Diana spent a total of 240 minutes attending a   [#permalink] 10 Sep 2016, 13:46
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