It is currently 12 Dec 2017, 21:34

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# You have 4 jars of pills. Each pill is a certain weight,

Author Message
SVP
Joined: 29 Aug 2007
Posts: 2470

Kudos [?]: 867 [0], given: 19

You have 4 jars of pills. Each pill is a certain weight, [#permalink]

### Show Tags

10 Sep 2008, 20:30
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

You have 4 jars of pills. Each pill is a certain weight, except for contaminated pills contained in one jar, where each pill is weight + 1. How could you tell which jar had the contaminated pills in just one measurement?
_________________

Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html

GT

Kudos [?]: 867 [0], given: 19

SVP
Joined: 07 Nov 2007
Posts: 1790

Kudos [?]: 1102 [0], given: 5

Location: New York

### Show Tags

10 Sep 2008, 21:10
GMAT TIGER wrote:
You have 4 jars of pills. Each pill is a certain weight, except for contaminated pills contained in one jar, where each pill is weight + 1. How could you tell which jar had the contaminated pills in just one measurement?

each pill weight =w
contaminated pill weight=w+1

Take different no of pills from 4 jackets.

For e.g
from Jar1 1 pill
from Jar 2 2 pills
from Jar 3 3 pills
from Jar 4 4

weight total pills = w+2w+3w+4w + x (x-- contaminated pills extra weight)
= 10w+x

once you measured the weight.. find x

if x=1 -- first jar
if x=2 second jar
if x=3 third jar.
if x=4 4th jar.

Where did you find this question..

very interesting..

It took 7 minutes to answer this question.
_________________

Smiling wins more friends than frowning

Kudos [?]: 1102 [0], given: 5

SVP
Joined: 29 Aug 2007
Posts: 2470

Kudos [?]: 867 [0], given: 19

### Show Tags

10 Sep 2008, 21:23
x2suresh wrote:
GMAT TIGER wrote:
You have 4 jars of pills. Each pill is a certain weight, except for contaminated pills contained in one jar, where each pill is weight + 1. How could you tell which jar had the contaminated pills in just one measurement?

each pill weight =w
contaminated pill weight=w+1

Take different no of pills from 4 jackets.

For e.g
from Jar1 1 pill
from Jar 2 2 pills
from Jar 3 3 pills
from Jar 4 4

weight total pills = w+2w+3w+4w + x (x-- contaminated pills extra weight)
= 10w+x

once you measured the weight.. find x

if x=1 -- first jar
if x=2 second jar
if x=3 third jar.
if x=4 4th jar.

Where did you find this question..

very interesting..

It took 7 minutes to answer this question.

you can find anywhere else. just google:

try this: Suppose you had 8 billiard balls, and one of them was slightly heavier, but the only way to tell was by putting it on a scale against another. What's the fewest number of times you'd have to use the scale to find the heavier ball?
_________________

Gmat: http://gmatclub.com/forum/everything-you-need-to-prepare-for-the-gmat-revised-77983.html

GT

Kudos [?]: 867 [0], given: 19

SVP
Joined: 17 Jun 2008
Posts: 1530

Kudos [?]: 282 [0], given: 0

### Show Tags

10 Sep 2008, 22:07
[quote="GMAT TIGER
try this: Suppose you had 8 billiard balls, and one of them was slightly heavier, but the only way to tell was by putting it on a scale against another. What's the fewest number of times you'd have to use the scale to find the heavier ball?[/quote]

Will it be 3?

step 1: 4 balls on each side of the scale. Get the heavier side balls.
step 2: 2 balls on each side of the scale from the lot of balls of heavier side in step 1. Get the heavier side balls.
step 3: 1 ball on each side of the scale. Get the heavier ball.

Kudos [?]: 282 [0], given: 0

SVP
Joined: 07 Nov 2007
Posts: 1790

Kudos [?]: 1102 [0], given: 5

Location: New York

### Show Tags

11 Sep 2008, 04:06
scthakur wrote:
[quote="GMAT TIGER
try this: Suppose you had 8 billiard balls, and one of them was slightly heavier, but the only way to tell was by putting it on a scale against another. What's the fewest number of times you'd have to use the scale to find the heavier ball?

Will it be 3?

step 1: 4 balls on each side of the scale. Get the heavier side balls.
step 2: 2 balls on each side of the scale from the lot of balls of heavier side in step 1. Get the heavier side balls.
step 3: 1 ball on each side of the scale. Get the heavier ball.[/quote]

agreed.

These questions... sound similar to sankunthala devi puzzles..
_________________

Smiling wins more friends than frowning

Kudos [?]: 1102 [0], given: 5

Re: Fun Math   [#permalink] 11 Sep 2008, 04:06
Display posts from previous: Sort by

# You have 4 jars of pills. Each pill is a certain weight,

Moderator: chetan2u

 Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.