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Bunuel received 13 Kudos for post If ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 0.

GiverPostDate
Ziko007If ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 013-Jun-2023
Navnit1If ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 016-Mar-2023
shubhamweek13If ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 011-Nov-2022
ShubhangiSangalIf ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 011-Aug-2022
Dhruva2000If ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 015-Jul-2022
ShivangiMittalIf ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 014-Jul-2022
sanyasanhaIf ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 014-Jul-2022
odonetgIf ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 010-Jul-2022
dvshjain1410If ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 004-Nov-2021
BAA5If ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 027-Oct-2021
FatehbirIf ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 019-Oct-2021
rawatkshitijIf ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 006-Oct-2021
maitreyi12If ab ≠ 0 and ax – by < 0, is x < y ? (1) a = b (2) a^3 > 015-Sep-2021

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