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Walkabout received 45 Kudos for post If the operation @ is defined by x@y=(xy)^1/2 for all.

GiverPostDate
NafissakibIf the operation @ is defined by x@y=(xy)^1/2 for all10-Feb-2024
BaThoLyIf the operation @ is defined by x@y=(xy)^1/2 for all03-Dec-2023
nilsbIf the operation @ is defined by x@y=(xy)^1/2 for all01-Dec-2023
NehmatIf the operation @ is defined by x@y=(xy)^1/2 for all04-Oct-2023
Bluebird30If the operation @ is defined by x@y=(xy)^1/2 for all03-May-2023
morganemyersIf the operation @ is defined by x@y=(xy)^1/2 for all02-May-2023
vamsi2025If the operation @ is defined by x@y=(xy)^1/2 for all10-Apr-2023
yannichcIf the operation @ is defined by x@y=(xy)^1/2 for all27-Mar-2023
MHammerIf the operation @ is defined by x@y=(xy)^1/2 for all27-Mar-2023
mayankdgmatIf the operation @ is defined by x@y=(xy)^1/2 for all26-Mar-2023
Sangeeta2405If the operation @ is defined by x@y=(xy)^1/2 for all26-Mar-2023
sachi123If the operation @ is defined by x@y=(xy)^1/2 for all03-Oct-2022
saracomiIf the operation @ is defined by x@y=(xy)^1/2 for all12-Sep-2022
Aravind04If the operation @ is defined by x@y=(xy)^1/2 for all16-May-2022
Rishabh86If the operation @ is defined by x@y=(xy)^1/2 for all13-Apr-2022
nisen20If the operation @ is defined by x@y=(xy)^1/2 for all05-Mar-2022
CaptainKorsakovIf the operation @ is defined by x@y=(xy)^1/2 for all04-Feb-2022
PangKjIf the operation @ is defined by x@y=(xy)^1/2 for all02-Oct-2021
Insane09If the operation @ is defined by x@y=(xy)^1/2 for all21-Jul-2021
Saba11If the operation @ is defined by x@y=(xy)^1/2 for all13-Apr-2021
campeanIf the operation @ is defined by x@y=(xy)^1/2 for all08-Mar-2021
NareliusIf the operation @ is defined by x@y=(xy)^1/2 for all11-Jan-2021
DD93If the operation @ is defined by x@y=(xy)^1/2 for all10-Jan-2021
VJ08If the operation @ is defined by x@y=(xy)^1/2 for all30-Dec-2020
Rahulchauhan16dIf the operation @ is defined by x@y=(xy)^1/2 for all14-May-2020
Nadja1234If the operation @ is defined by x@y=(xy)^1/2 for all01-Mar-2020
analytica233If the operation @ is defined by x@y=(xy)^1/2 for all28-Dec-2019
Sahera5If the operation @ is defined by x@y=(xy)^1/2 for all02-Dec-2019
kaladin123If the operation @ is defined by x@y=(xy)^1/2 for all11-Nov-2019
philippiIf the operation @ is defined by x@y=(xy)^1/2 for all04-Oct-2019

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