GMAT Club

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petrifiedbutstanding received 21 Kudos for post If x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?.

GiverPostDate
JacobtIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?07-Aug-2020
twobagelsIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?01-Aug-2020
SssgIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?26-May-2020
soninhabbmIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?25-May-2020
1anant1If x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?18-May-2020
IlmisraelIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?16-Mar-2020
RebazIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?13-Mar-2020
Ujjwal97If x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?13-Feb-2020
analytica233If x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?03-Jan-2020
tarudashoriyaIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?07-Sep-2019
bartkIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?14-Jul-2019
wls29943If x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?17-Feb-2019
razeeIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?22-Jan-2019
dave13If x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?03-Jan-2019
CLIMBTHELADDERIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?29-Dec-2018
PreethiVishwanathanIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?15-Aug-2018
yetskiIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?19-Jul-2018
rishavaggarwalIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?15-Jul-2018
duahsoloIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?17-Jun-2018
RidhimaNigamIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?17-Oct-2016
FabiNIf x ≠ 0 and x = (4xy - 4y^2)^(1/2), then in terms of y, x = ?26-Jul-2016

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