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\(\sqrt{2}­\)­ + \(\frac{1}{2+\sqrt{2}}\)­ + \(\frac{1}{\sqrt{2}-2}\)­ =­

A. 0
B. 2
C. \(\frac{\sqrt{2}}{2}\)
D. \(\sqrt{2}\)
E. \(2\sqrt{2}­\)­
­

­
Check here: https://gmatclub.com/forum/topic-426759.html

Hope it helps.






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Statistics : Posted by Bunuel • on 21 Apr 2024, 14:35 • Replies 1 • Views 88


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dc.econ wrote:

\(\sqrt{2}­\)­ + \(\frac{1}{2+\sqrt{2}}\)­ + \(\frac{1}{\sqrt{2}-2}\)­ =­

A. 0
B. 2
C. \(\frac{\sqrt{2}}{2}\)
D. \(\sqrt{2}\)
E. \(2\sqrt{2}­\)­
­

­
Check here: https://gmatclub.com/forum/topic-426759.html

Hope it helps.






Archived Topic




Hi there,

This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.



Where to now? Join ongoing discussions on thousands of quality questions in our Problem Solving (PS) Forum












Still interested in this question?
Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.

Thank you for understanding, and happy exploring!


]]>
(Bunuel)Sun, 21 Apr 2024 14:44:51 -0800https://gmatclub.com:443/forum/viewtopic.php?p=3387086#p3387086