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A chocolate box has a long triangular shape. The triangular

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A chocolate box has a long triangular shape. The triangular [#permalink] New post 30 Nov 2012, 15:03
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88% (01:35) correct 13% (02:47) wrong based on 16 sessions
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A chocolate box has a long triangular shape. The triangular shaped end piece is an equilateral triangle. The length of the box is 5\sqrt{3} inches, and the volume is 135. What is the value of x in inches?

A. \frac{9}{\sqrt{3}}
B. 3
C. 6
D. 9
E. 9\sqrt{3}
[Reveal] Spoiler: OA

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Last edited by Bunuel on 01 Dec 2012, 05:30, edited 1 time in total.
Renamed the topic and edited the question.
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Re: Geometry Problem Help [#permalink] New post 30 Nov 2012, 15:32
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You know that the Volume V=Area of the triangle * length --> Area = \frac{V}{length} = \frac{135}{5*\sqrt{3}} = \frac{27}{\sqrt{3}}
Then
Use the formula Area = a^2* \sqrt{3}/2

Thus a^2 = 27/\sqrt{3}*4/\sqrt{3} = 27*4/3= 36 then a=\sqrt{36} = 6

C
Re: Geometry Problem Help   [#permalink] 30 Nov 2012, 15:32
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A chocolate box has a long triangular shape. The triangular

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