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# A chocolate box has a long triangular shape. The triangular

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Joined: 06 Sep 2012
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Concentration: Social Entrepreneurship
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Kudos [?]: 21 [1] , given: 42

A chocolate box has a long triangular shape. The triangular [#permalink]  30 Nov 2012, 15:03
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Question Stats:

85% (01:45) correct 15% (03:52) wrong based on 20 sessions
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Ttriangular.png [ 6.89 KiB | Viewed 1056 times ]
A chocolate box has a long triangular shape. The triangular shaped end piece is an equilateral triangle. The length of the box is $$5\sqrt{3}$$ inches, and the volume is 135. What is the value of x in inches?

A. $$\frac{9}{\sqrt{3}}$$
B. 3
C. 6
D. 9
E. $$9\sqrt{3}$$
[Reveal] Spoiler: OA

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Last edited by Bunuel on 01 Dec 2012, 05:30, edited 1 time in total.
Renamed the topic and edited the question.
Intern
Joined: 26 Nov 2012
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Concentration: Finance, General Management
GMAT Date: 02-05-2013
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Kudos [?]: 3 [3] , given: 2

Re: Geometry Problem Help [#permalink]  30 Nov 2012, 15:32
3
KUDOS
You know that the Volume $$V=Area of the triangle * length --> Area = \frac{V}{length} = \frac{135}{5*\sqrt{3}} = \frac{27}{\sqrt{3}}$$
Then
Use the formula $$Area = a^2* \sqrt{3}/2$$

Thus $$a^2 = 27/\sqrt{3}*4/\sqrt{3} = 27*4/3= 36$$ then $$a=\sqrt{36} = 6$$

C
Re: Geometry Problem Help   [#permalink] 30 Nov 2012, 15:32
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