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DS- Geometry

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DS- Geometry [#permalink] New post 19 Oct 2005, 19:09
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
See attached

[EDITED THE DIAGRAM]
Attachments

triangle_403.gif
triangle_403.gif [ 5.79 KiB | Viewed 649 times ]


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-Vikram


Last edited by vikramm on 19 Oct 2005, 20:07, edited 1 time in total.
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 [#permalink] New post 19 Oct 2005, 20:03
1) insuff coz you can form many triangles ABC with C and B are intersection points between any tangents to the circle with two sides of the angle A.
2) sorry, I can not attach my illustration ( in paint file) here.
As vikramm just edited the picture, A in my solution is indeed C in his picture and vice versa

You can easily prove that AE is indeed AD.
We have angle FOD= 360- (90+90+45) = 135 --->AOF= 180-135=45--->OAF= 445 or DAB= 45
We also have EAB=45
DAB=EAB= 45 -----> AD is indeed AE.
AD= sqrt 2, OD=1 ==> AD= 1+ sqrt 2
AD=1/2 BC ( Coz AB=AC ---> AD is also the median of right triangle ABC) ----> BC= 2*AD= 2+2*sqrt2
Area of ABC= AD*BC/2= (1+sqrt 2)^2


1 and 2 must be together to be sufficient to provide answer. C is correct.


NOTE: You'd better open the doc file in seperate page so that you can understand my explanation. I'm badly sorry for my clumsy illustration coz I know no other means to draw some illustration. :oops: :oops: :oops:
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Last edited by laxieqv on 19 Oct 2005, 20:19, edited 3 times in total.
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 [#permalink] New post 19 Oct 2005, 20:08
My bad... I edited the diagram.
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  [#permalink] 19 Oct 2005, 20:08
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