can anyone help me out with this?.....the answer is D:
25. The surface area of a square tabletop was changed so that one of the dimensions was reduced by 1 inch and the other dimension was increased by 2 inches. What was the surface area before these changes were made?
(1) After the changes were made, the surface area was 70 square inches.
Since it is a sqaretop, let side =x, Hence (x-1)(x+2)= 70
Solving you get x=8 SUFF
(2) There was a 25 percent increase in one of the dimensions.
Since there was a 1/4 increase, 1/4 * x = 2 i.e. x=8 SUFF