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# math question

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math question [#permalink]  05 Jan 2010, 19:40
Which of the following fractions has the greatest value?

a) [3][/8!]

b) [6(4!)][/5(9!)]

c) [4(3!)][/9!]

d) [3][/5(7!)]

e) [14][/5(8!)]

I'm having some difficulties solving this one. Can someone help me!
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Re: math question [#permalink]  06 Jan 2010, 10:27
I'll apply some formatting:

Which of the following fractions has the greatest value?

a)\frac {3}{8!}

b) \frac{6(4!)}{5(9!)}

c)\frac{4(3!)}{9!}

d) \frac{3}{5(7!)}

e) \frac{14}{5(8!)}
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Re: math question [#permalink]  06 Jan 2010, 10:38
a)\frac {3}{8!}

b) \frac{6(4!)}{5(9!)} = \frac{3.2}{8!}

c)\frac{4(3!)}{9!} = \frac{2.(6)}{8!}

d) \frac{3}{5(7!)} = \frac{4.8}{8!} < - - - Greatest fraction

e) \frac{14}{5(8!)}= \frac{2.8}{8!}
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Re: math question [#permalink]  06 Jan 2010, 10:55
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Re: math question [#permalink]  06 Jan 2010, 11:07
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ppaulyni3 wrote:

You should manipulate fractions in order to get them to some common denominator. Then the one with greatest numerator has the greatest value

The math here is quite simple.

9! = 8! * 9

To get 8! from 7! in answer (d) you should multiply both the numerator and denominator by 8 : 7! * 8 = 8!

These are the only points worth mentioning
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Re: math question [#permalink]  07 Jan 2010, 06:38
ppaulyni3 wrote:
Which of the following fractions has the greatest value?

a) [3][/8!]

b) [6(4!)][/5(9!)]

c) [4(3!)][/9!]

d) [3][/5(7!)]

e) [14][/5(8!)]

I'm having some difficulties solving this one. Can someone help me!

convert the fractions to some common factor

a)[3/8!]=k*(3/8)

b) [6(4!)][/5(9!)]=k*(4!/60)

c) [4(3!)][/9!]=k*{(4*3!)/72}

d) [3][/5(7!)]=k*(3/5)

e) [14][/5(8!)]=k*(14/40)

where k =(1/7!)
it is easy to solve it now..clearly D has the maximum value
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Re: math question   [#permalink] 07 Jan 2010, 06:38
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# math question

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