Three cards are drawn from a 52 card deck - no replacement. What is the probability that the last two draws are aces if the first was an ace?
Please explain the method
After the first draw, 51 cards left in the desk, of which 3 are aces. (Since first draw was an ace).
So probability of drawing an ace in the second draw = 3/51
Now, there are 50 cards left and 2 aces
So probability of drawing an ace in the third draw = 2/50
Hence probability of drawing 2 aces after the first one is an ace = 3/51 * 2/50 = 1/425
1) Algebra-101 2) Sequences 3) Set combinatorics 4) 3-D geometry
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