gmat2me2 wrote:

kapslock wrote:

mirhaque wrote:

hmm........

The area of the square would be > 1 if perimeter > 4.

Thus the "allowed" length of the wire to be cut is upto 1 m from either end.

Thus 2 m out of 5 m is the allowed "cuttable" length.

0..........1............2............3.............4..............5

---------------------------------------------------------

|cuttable|..........................................|.cuttable.|

Thus probability = 0.4.

If you are cutting exactly 1 m still your not getting area >1 right?

You're right, but this is a case of limits.

Lets put it this way.

If cuttable length (on either side) = 0.5 m, area = 1.265625

If cuttable length (on either side) = 0.75 m, area = 1.1289

If cuttable length (on either side) = 0.875 m, area = 1.06347

If cuttable length (on either side) = 0.95 m, area = 1.02515

If cuttable length (on either side) = 0.99 m, area = 1.00500625

If cuttable length (on either side) = 0.999 m, area = 1.0005

So you see, as Limit (cuttable length -> 1), area -> 1.

And as Limit (cuttable length -> 1), p -> 0.4.

Hope that helps.

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