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I know this will be a easy question for a lot of you.. but i really didnt understand the solution.. can someone help
The ratio, by weight, of coffee to mate to water in a certain cup of coffee is 6:2:15. The coffee is altered so that the ratio of coffee to mate is halved while the ratio of coffee to water is doubled. If the altered coffee will contain 16 grams of mate, how many grams of water does it contain after alteration? 13 (A) 12 (B) 15 (C) 30 (D) 60 (E) 100 Solution The current ratio of coffee to mate is 6:2, when halved, the ratio becomes 3:2 or 6:4 or 12:8. The current ratio of coffee to water is 6:15, when doubled, the ratio is 12:15. The ratio of cofee to mate to water, when combined, becomes 12:8:15. Based on the ratio 12:8:15, the total grams t was divided as follows: t 38 10 was coffee, t 38 8 was mate, and t 38 15 was water. Since t 38 8 = 16, t = (16) 76 8 38 = and then 76 30 38 15 38 15 t = × = . So the correct answer choice is C.
C:M:W=6:2:15 C:M is halved so C:M=3:2 C:W is doubled = 12:15 Now M:C =2:3 and C:W=12:15 M:C=8:12 C:W=12:15 M:C:W=8:12:15 New mix contains 16gms of Mate 8x=16 x=2 Water will be 15x=15*2=30gms _________________
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