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# Slopes Relation

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Slopes Relation [#permalink]  24 Feb 2011, 03:21
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 100% (00:04) wrong based on 1 sessions
I think answer is wrong as

am=-1 when two lines are perpendicular.

Pls Comment
[Reveal] Spoiler: OA

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relation between slopes.JPG [ 18.03 KiB | Viewed 1091 times ]

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Re: Slopes Relation [#permalink]  24 Feb 2011, 03:51
Is this the entire question ?
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Re: Slopes Relation [#permalink]  24 Feb 2011, 04:59
B is the odd man out. B can't coexist with the rest of the options.

a=1; m=1; b,d=0

All are true but B.
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Re: Slopes Relation [#permalink]  24 Feb 2011, 20:47
Hi

I did not get why B is the odd man out, please explain.

Regards,
Subhash
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Re: Slopes Relation [#permalink]  24 Feb 2011, 22:15
subhashghosh wrote:
Hi

I did not get why B is the odd man out, please explain.

Regards,
Subhash

This solution could be best explained with a figure;

When do you think the slopes of two lines are equal; either when they are parallel to each other or when they overlap.

Let's consider the case when they coincide:
So; the slopes are equal. "2". and both the lines intercept y-axis at same point. Thus, b=d. With these conditions; all of the
given options but B are possible.

a=m=2
am=-1. Not possible because=2*2=4; not -1
a^2=m^2=2^2=4
$$|2|=\sqrt{m^2}=\sqrt{2^2}=2$$
$$am=2*2>0$$

For parallel lines as well; all of the above hold true; because parallel lines have same slope

Let's consider two parallel lines with -ve slope = -3. The only difference in parallel lines and coinciding lines is that they intercept y-axis at different points. Here; we don't care about b or d(y-intercept).
a=m=-3
am=-3*-3=9!=-1
a^2=m^2=(-3)^2=9
$$|a|=\sqrt{m^2}=3$$
am=-3*-3>0

When the lines are not parallel; their slopes will not be equal. For unequal slopes;
Say a=1; m=2 or anything other than 1.
A. a!=m
B. am!=-1
C. a^2!=m^2

Thus; these options don't hold good for two lines with different slopes.

What if these two lines are perpendicular;
a=-1; m=1

a!=m
am=-1. Possible
a^2=m^2=1. Possible
$$|1|=\sqrt{m^2}=\sqrt{(-1)^2}=1$$ Possible
am=-1<0. Not possible.
We see that A and E both aren't true for the perpendicular lines.

Thus; we can conclude that the given equations are equation of parallel lines or overlapping lines, where option B is the odd man out.
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Re: Slopes Relation [#permalink]  25 Feb 2011, 03:34
You're saying:

am=-1. Possible

am=-1<0. Not possible.

How so ?
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Re: Slopes Relation [#permalink]  25 Feb 2011, 04:20
subhashghosh wrote:
You're saying:

am=-1. Possible

am=-1<0. Not possible.

How so ?

option E. am>0; but when the lines are perpendicular
a=1 m=-1
a*m=1*-1=-1
-1<0 not greater than 0.
So option E is ruled out.

am=-1 means option B holds true or B is possible.
*******************
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Re: Slopes Relation [#permalink]  25 Feb 2011, 05:25
I am not getting this reasoning at all. Bunuel, please come to rescue !
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Re: Slopes Relation   [#permalink] 25 Feb 2011, 05:25
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