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26 Aug 2012, 02:59
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D
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Difficulty:
5%
(low)
Question Stats:
94% (00:42) correct
6%
(01:10)
wrong
based on 3524
sessions
History
Date
Time
Result
Not Attempted Yet
\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}\)
(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3
(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3
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26 Aug 2012, 02:59
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SOLUTION:
\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}\)
(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3
\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}= \)
\( =\frac{1}{(\frac{4}{3})}-\frac{1}{(\frac{3}{2})}= \)
\( =\frac{3}{4}-\frac{2}{3}= \)
\( =\frac{1}{12}\).
Answer: D.
\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}\)
(A) -1/3
(B) -1/6
(C) -1/12
(D) 1/12
(E) 1/3
\(\frac{1}{1+\frac{1}{3}}-\frac{1}{1+\frac{1}{2}}= \)
\( =\frac{1}{(\frac{4}{3})}-\frac{1}{(\frac{3}{2})}= \)
\( =\frac{3}{4}-\frac{2}{3}= \)
\( =\frac{1}{12}\).
Answer: D.
General Discussion
mcelroytutoring
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Joined: 10 Jul 2015
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Expert reply
10 May 2016, 18:18
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Attached is a visual that should help.
Attachments
Screen Shot 2016-05-10 at 5.50.27 PM.png [ 75.73 KiB | Viewed 56744 times ]
