1- +6)+7] = -2 0 1 2 16 : Quant Question Archive [LOCKED]
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# 1- +6)+7] = -2 0 1 2 16

Author Message
Director
Joined: 12 Jun 2006
Posts: 532
Followers: 2

Kudos [?]: 116 [0], given: 1

1- +6)+7] = -2 0 1 2 16 [#permalink]

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16 Aug 2007, 20:16
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

1-[2-(3-[4-5]+6)+7] =

-2
0
1
2
16
Director
Joined: 12 Jun 2006
Posts: 532
Followers: 2

Kudos [?]: 116 [0], given: 1

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16 Aug 2007, 20:56
Director
Joined: 03 May 2007
Posts: 886
Schools: University of Chicago, Wharton School
Followers: 6

Kudos [?]: 188 [0], given: 7

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16 Aug 2007, 21:02
ggarr wrote:

= 1 - [2 - (3 - [4 - 5] + 6) + 7]
= 1 - [2 - (3 - [-1] + 6) + 7]
= 1 - [2 - (3 + 1 + 6) + 7]
= 1 - [2 - 10 + 7]
= 1 - [-1]
= 1 + 1
= 2
Intern
Joined: 24 Jan 2006
Posts: 5
Followers: 0

Kudos [?]: 7 [0], given: 0

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16 Aug 2007, 22:43
Ans is 2.

I think the order is unimportant, as long as you unfold the signs properly.

1-[2-(3-[4-5]+6)+7]
1-2+(3+6+1)-7
-9 + 11
= 2.

Other combinations will also yield 2, but make sure you flip the signs properly as you unfold the [] or ().
Manager
Joined: 14 May 2006
Posts: 202
Followers: 1

Kudos [?]: 11 [0], given: 0

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17 Aug 2007, 00:52
2

Wouldn't this be in like the lower-bin questions? No offense ggarr.
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