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# Absolute

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VP
Joined: 06 Feb 2007
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06 Apr 2007, 18:24
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

|x| > |y| ?

1) x^2 > y^2

2) x > y

Director
Joined: 14 Jan 2007
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06 Apr 2007, 19:24

stmt 1: x^2 > y^2
irrespective of the sign of x and y, stmt1 proves that |x| >| y|
hence SUFF

stmt2: x > y
for +ve x and +ve y stmt2 gives |x| >| y|
for -ve x and -ve y stmt2 gives |x| <| y|
hence INSUFF
GMAT Club Legend
Joined: 07 Jul 2004
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06 Apr 2007, 20:19
St1:
Sufficient. Works for both negative and positive values. If x = 3, y = 2, x^2 > y^2 and |x| > |y|. It works for x = -3 and y = -2 as well.

St2:
Works only for positive values. If x = -2 and y = -3, then |x| < |y|. Insufficient.

Ans A
Manager
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06 Apr 2007, 20:21
nervousgmat wrote:
|x| > |y| ?

1) x^2 > y^2

2) x > y

1) if x^2 > y^2 this means that on a number line we have something like this

-infinity ... -x ... -y ... 0 ... y ... x ... +infinity. This shows that 1 is SUFF

Now for 2) if x = -1 and y = -2 then x > y but |x| <y> y and |x| > |y|. Hence INSUFF

VP
Joined: 06 Feb 2007
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07 Apr 2007, 09:25
The OA is A.

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