Absolute values : Quant Question Archive [LOCKED]
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# Absolute values

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Director
Joined: 22 Aug 2007
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03 Sep 2007, 00:40
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

ds
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SVP
Joined: 01 May 2006
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03 Sep 2007, 01:04
(C) for me

|x| < 4
<=> -4 < x < 4

From (1)
x is divisable by 3
<=> x = 3*k where k is an integer
=> x=-3 or x=0 or x=3

INSUFF.

From (2)
x is divisable by 2
<=> x = 2*j where j is an integer
=> x=-2 or x=0 or x=2

INSUFF.

Both (1) & (2)
Only 0 could satisfy both statments.

SUFF.
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03 Sep 2007, 01:12
St1:
x can be 0,-3 or 3. Insufficient.

St2:
x can be 0,-2 or 2. Insufficient.

Using both st1 and st2:
x must be 0. The remaining integers divisible by both 2 and 3 are multiples of 6, which falls out of the boundary set by |x| < 4.

Ans C
03 Sep 2007, 01:12
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