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Age Problem?

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Manager
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Age Problem? [#permalink] New post 01 Sep 2007, 08:53
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Please provide your answer and explanation

Q) Andrew will be half as old as Larry in 3 years. Andrew will also be one-third as old as Jerome in 5 years. if Jerome is 15 years older than Larry, how old is Andrew?.

I'm struggling with the age problem in general. Is there a good method to solve these problems?
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 [#permalink] New post 01 Sep 2007, 08:58
Is Anderw 8 yrs old. If right, I'll give the explanation.
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 [#permalink] New post 01 Sep 2007, 09:00
Yes, Andrew is 8 years old
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 [#permalink] New post 01 Sep 2007, 09:04
Ok.

Just write equations as u read the ques.

A+3 = 1/2(L+3)
=> 2A + 3 = L ----(1)

A + 5 = 1/3 (J+5)
=> 3A + 10 = J
Since J = L + 15

=> 3A - 5 = L ---(2)

Using (1) and (2)

A = 8
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Re: Age Problem? [#permalink] New post 01 Sep 2007, 09:08
tinman1412 wrote:
Please provide your answer and explanation

Q) Andrew will be half as old as Larry in 3 years. Andrew will also be one-third as old as Jerome in 5 years. if Jerome is 15 years older than Larry, how old is Andrew?.

I'm struggling with the age problem in general. Is there a good method to solve these problems?


Best way to do these problems is to write out every date.

Now || 3yrs from now || 5yrs from now
A || A+3 || A+5
J || J+3 || J+5
L || L+3 || L+5

Now make the equations for the appropriate years.

Since Andrew will be half as old as jerome in 3 years. you can rewrite it like this: 2(A+3)=L+3

Next equation: rewrite it just like above. Make the two sides equal to each other.

3(A+5)=J+5

Final one 15+L=J (since J is 15yrs older, adding 15 to L will equal J).

Now solve:
J=15+L--> 3(A+5)=J+5--> 3A+15=15+L+5 --> 3A-5=L

2(A+3)=L+3--> 2A+6=3A-5+3 -->2A+6=3A-2 ---> A=8
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 [#permalink] New post 01 Sep 2007, 09:15
Very helpful explantion. Thanks,
  [#permalink] 01 Sep 2007, 09:15
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