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# Another one

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Manager
Joined: 28 Aug 2006
Posts: 245
Location: Albuquerque, NM
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Another one [#permalink]  03 Jan 2007, 22:06
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Senior Manager
Joined: 19 Jul 2006
Posts: 361
Followers: 1

Kudos [?]: 3 [0], given: 0

C

From (1) under age of 50 : 16% have retirement savings
29% of total populations have retirement savings
Insufficient

From (2) Number of people under age of 50 > Number of people over age of 50
Insufficient

From (1) and (2)

Say the total population is 100.

Taking the boundary condition:
Number of people under age of 50 = 51
Number of people over age of 50 = 49

29 people have retirement savings

Number of people under age of 50 and having retirement savings = 16 % = .16* 51 = 9

Number of people over age of 50 and having retirement savings = 29-9= 20
= (20/49)* 100 = 40.8 % (this is the least % )
Manager
Joined: 28 Aug 2006
Posts: 245
Location: Albuquerque, NM
Followers: 1

Kudos [?]: 1 [0], given: 0

Wow good method, taking the population as 100 helped here

Thanks
Senior Manager
Joined: 24 Nov 2006
Posts: 351
Followers: 1

Kudos [?]: 16 [0], given: 0

(1) LetÂ´s say A = # of ppl under the age of 50, and B = # of ppl over the age of 50.

Let n = % of ppl over 50 who have some form of retirement savings.

What (1) says is that

(16%A + n%B) / (A + B) = 29%. Solving:

(n - 29)%B = 13%A

(n - 29)/13 = A/B

This is clearly insufficient to determine whether at least 40% of those over 50 have retirement savings.

(2) says that A < B. This, alone, is insufficient as well.

(1&2) We have: (n - 29)/13 = A/B < 1. Therefore, n < 42. n could be greater or smaller than 40. Insuff => E.
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