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another question [#permalink]

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New post 13 May 2004, 18:28
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

I have another math question

The width of rectangle A is 1/2 the width of Rectangle B. If the ratio of length to width of rectangle A is 3:2 and the ratio of length to width of rectangle B is 5:2 then what is the ratio of the areas of rectangle A to B.

Last edited by pieceofmoon on 13 May 2004, 19:21, edited 1 time in total.
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Re: another question [#permalink]

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New post 13 May 2004, 18:36
w1/w2 = 1/2
w1/a1 = 2/3
w2/a2 = 2/5, find w1*a1/(w2*a2)

(2/3)/(2/5) = (1/2)(a2/a1)
10/3 = a2/a1

ans = (1/2)(3/10) = 3/20
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 [#permalink]

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New post 13 May 2004, 19:59
What you can also do is pick numbers
W1 = 4
L1 = 6
W2 = 8
L2 = 20
where:
W1/W2 = 4/8 = 1/2
L1:W1 = 6:4 = 3:2
L2:W2 = 20:8 = 5:2

W1L1 / W2L2 = 6*4 / 20*8 = 24/160 = 3/20
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Re: another question [#permalink]

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New post 14 May 2004, 05:04
pieceofmoon wrote:
I have another math question

The width of rectangle A is 1/2 the width of Rectangle B. If the ratio of length to width of rectangle A is 3:2 and the ratio of length to width of rectangle B is 5:2 then what is the ratio of the areas of rectangle A to B.


WB = x, WA = x/2, LA = 3/2*x/2 = (3/4)x.

LB = 5/2x => SA/SB = (3/8)/[5/2] = 3/20.
Re: another question   [#permalink] 14 May 2004, 05:04
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