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challenge 25 question 2

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challenge 25 question 2 [#permalink] New post 31 May 2006, 12:36
plz Explain your reasoning and approach to this one
Explanations given are not clear


how many integers divisible by 3 are there betwen 10! and 10!+20

6
7
8
9
10



thanks
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 [#permalink] New post 31 May 2006, 12:43
I will go with 7. And Explanation goes as

10! is divisible by 3
and between 10! and 10!+ 20 there are 6 integers divisible by 3 ( 10!+3, 10!+6, 10!+9, 10!+12, 10!+15, 10!+18)

So total 7 integers are there between 10! and 10!+20 that are divisible by 3.


Please correct me if iam wrong
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 [#permalink] New post 31 May 2006, 13:06
7

10! is divisible by 3. Others are 10!+3, 10!+6........10!+18
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 [#permalink] New post 31 May 2006, 14:14
I would say 6 since the problem says BETWEEN 10! and 10! + 20.

However, if it were inclusive of 10!, then the answer would be 7.
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 [#permalink] New post 31 May 2006, 14:24
:-D thanks for urs explanation answer is 7 so it is inclusive i guess
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Re: challenge 25 question 2 [#permalink] New post 03 Jun 2006, 04:33
mand-y wrote:
plz Explain your reasoning and approach to this one
Explanations given are not clear


how many integers divisible by 3 are there betwen 10! and 10!+20

6
7
8
9
10

thanks


I would go for 6.
It's between 10! and 10! +20.
There are 6 numbers between 1 and 20 which can be divisible by 3.

Regards,
Brajesh
Re: challenge 25 question 2   [#permalink] 03 Jun 2006, 04:33
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