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# challenge 25 question 2

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Manager
Joined: 05 Oct 2005
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challenge 25 question 2 [#permalink]  31 May 2006, 11:36
plz Explain your reasoning and approach to this one
Explanations given are not clear

how many integers divisible by 3 are there betwen 10! and 10!+20

6
7
8
9
10

thanks
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when there is a will there is a way

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Intern
Joined: 29 Apr 2006
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I will go with 7. And Explanation goes as

10! is divisible by 3
and between 10! and 10!+ 20 there are 6 integers divisible by 3 ( 10!+3, 10!+6, 10!+9, 10!+12, 10!+15, 10!+18)

So total 7 integers are there between 10! and 10!+20 that are divisible by 3.

Please correct me if iam wrong
CEO
Joined: 20 Nov 2005
Posts: 2913
Schools: Completed at SAID BUSINESS SCHOOL, OXFORD - Class of 2008
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7

10! is divisible by 3. Others are 10!+3, 10!+6........10!+18
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SAID BUSINESS SCHOOL, OXFORD - MBA CLASS OF 2008

Manager
Joined: 10 May 2006
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Location: USA
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I would say 6 since the problem says BETWEEN 10! and 10! + 20.

However, if it were inclusive of 10!, then the answer would be 7.
Manager
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thanks for urs explanation answer is 7 so it is inclusive i guess
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Director
Joined: 17 Sep 2005
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Re: challenge 25 question 2 [#permalink]  03 Jun 2006, 03:33
mand-y wrote:
plz Explain your reasoning and approach to this one
Explanations given are not clear

how many integers divisible by 3 are there betwen 10! and 10!+20

6
7
8
9
10

thanks

I would go for 6.
It's between 10! and 10! +20.
There are 6 numbers between 1 and 20 which can be divisible by 3.

Regards,
Brajesh
Re: challenge 25 question 2   [#permalink] 03 Jun 2006, 03:33
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