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Manager
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Circles [#permalink] New post 26 Oct 2003, 15:22
I find do not quite get the answer from OG for the attached question.

From OG, ... the number of rotations per second of the larger rim is 28/35
times the number of rotations of the smaller rim.

Does anyone has a solution with a simplified workings?
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 [#permalink] New post 27 Oct 2003, 11:42
smaller rim makes x revs/sec which is 60x revs/min

the smaller rim is only 28/35 = 4/5 the size of the larger rim

therefore when the smaller rim makes 60x revs in a minute and they are spining at the same speed (in terms of movement). the larger rim will make (4/5)*60x revs in one minute.

at least that's how i did it.
  [#permalink] 27 Oct 2003, 11:42
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