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Computer and Printer---Prep Question

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Director
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Computer and Printer---Prep Question [#permalink] New post 18 Jul 2009, 09:29
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions
Computer and Printer---Prep Question

I am not agree with the answer...please explain
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Re: Computer and Printer---Prep Question [#permalink] New post 18 Jul 2009, 10:13
Let the price of the basic computer be b
Let the price of the printer be p
given

b+p = 2500 ------ 1

Now given

Enhanced computer is 500 more then basic computer
Let price of enhanced computer be e

\Rightarrow e = b+500 ---- 2

Also given price of the printer is one fifth of the total price of the enhanced computer and the printer.

\Rightarrow p = \frac{1}{5} \times (e+p)

\Rightarrow p= \frac{1}{5} \times (b+500+p)

\Rightarrow 5p=b+500+p

\Rightarrow b-4p=(-500) ---- 3

Subtracting 3from1 gives us

\Rightarrow 5p = 3000

\Rightarrow p=600

From 1

b+p=2500

b+600=2500

b=2500-600

b=1900

Answer is D.
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Re: Computer and Printer---Prep Question [#permalink] New post 18 Jul 2009, 21:13
Variables

basic computer = bc
printer = p
enhanced computer = ec
First total = FT
Second total = ST


bc + p = 2500 ..... 1
FT = 2500

ec = bc + 500 .... 2

ec + p = 2500 + 500 (the question says enhanced computer is 500 more than the original computer)
therefore ec + p = 3000
ST = 3000

p = 1/5*ST = 600

ec = 3000 - p = 3000 - 600 = 2400

bc = ec - 500 = 2400 - 1000 = 1900

Answer is D
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Re: Computer and Printer---Prep Question [#permalink] New post 28 Jul 2009, 12:22
B + P = 2500

E = B + 500

P = (B + 500)/4

B + (B + 500)/4 = 2500

(5/4)B +125 = 2500

(5/4)B = 2375

B = 1900

So answer is D.

I think you are confusing the meaning of "1/5 of the total". It means that the printer is 1/5 of the Enhanced computer and printer combined, not the Enhanced computer alone. Therefore P = (B + 500)/4, NOT P = (B + 500)/5.
Re: Computer and Printer---Prep Question   [#permalink] 28 Jul 2009, 12:22
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